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dmitriy555 [2]
3 years ago
8

A car accelerates from rest to 37.3 m/s in 7 sec. What is the acceleration?

Physics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

poopgshshsh

Explanation:

cacawusususu

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How does the speed of a sound wave change as the medium through which it traveks changes?
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Increase as density increase and vise versa.
<span>The wavelength increases when a sound wave travels from a less dense to a more dense medium, the speed increases, and the frequency stays the same.</span>
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As you run , your feet push on the ground with a force 500N . The ground pushes back on your feet with a force of 500N . (Please
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Answer:

true

Explanation:

newtons third law says to every action there is always an equal and opposite reaction. so the answer is true

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Which of the following describes the renewability of utility-scale wind energy?
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Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

<h3>What is utility-scale wind energy?</h3>

Utility-scale wind turbines are installed in large, multi-turbine wind farms connected to the nation's transmission system. These turbines produce clean and unlimited energy.

So we can conclude that Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

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Why does saturn and jupiter have more moons than the other planets in our solar system ?
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You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
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