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Juliette [100K]
2 years ago
13

The speed of a chemical reaction

Chemistry
1 answer:
Ede4ka [16]2 years ago
5 0

Answer Option c. between gases should in all cases be extremely rapid because the average kinetic energy of the molecules is great.

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A scuba diver is using scuba gear to breathe under water. The pressure on her lungs is 2.5 atm and her lung volume is 4.4 L. Wha
nikdorinn [45]

Answer:

<h2>2.44 L</h2>

Explanation:

The volume can be used by using the formula for Boyle's law which is

P_1V_1 = P_2V_2 \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

We have

V_2 =  \frac{2.5 \times 4.4}{4.5}  =  \frac{11}{4.5}  \\  = 2.444444....

We have the final answer as

<h3>2.44 L</h3>

Hope this helps you

3 0
3 years ago
Use the Periodic Table of the Elements to answer
Juliette [100K]

Answer:

b. lithium

Explanation:

Li the least likely, to lose an electron.

6 0
3 years ago
Which term names the concentration of salts dissolved in a liquid?
Viefleur [7K]
Hey there!
The answer is D, Salinity.
Salinity is the concentration of salt in water. Ocean water often has high salinity and this can contribute to things like upwelling and water density- but these all start from salinity.
Hope this helps!
4 0
3 years ago
Read 2 more answers
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
2 years ago
5.58e-18 + 8.65e-13 / -8.76e+06
evablogger [386]

Answer:

this is the answer:

− 10.13099839

Explanation:

5 0
3 years ago
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