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3 years ago

NEED ANSWER ASAP PLEASE

Mathematics

2 answers:

Kay [80]3 years ago

5 0

Answer:

<h2>After 1 hour and 24 minutes.</h2>

Step-by-step explanation:

The turtle.

It gets 7 kilometers head start.
Its speed is 2 kilometers per hour.

The rabbit.

It doesn't get any head start.
Its speed is 7 kilometers per hour.

We know that, $v_{turtle} = 2km/hr$ and $v_{rabbit}= 7km/hr$

Assuming both have a constant movement, we define each one with

$d=vt$

$d_{rabbit}=v_{rabbit}t$ and $d_{turtle}=v_{turtle}t$ , replacing values, we have

$d=7t$ which is the distance of the rabbit, and we know the turtle's is +7, so

$d=2t+7$ .

Now, we substute the first equation into the second one,

$7t=2t+7\\7t-2t=7\\5t=7\\t=\frac{7}{5}hr$

If we divide, we'll have a mixed number

$t=\frac{7}{5}=1\frac{2}{5}= 1 \ hr \ 24 \ min$

Therefore, the time they will meet is after 1 hour and 24 minutes.

ollegr [7]3 years ago

3 0

I don't get how it would be a system of equations.

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Please help me on this

garri49 [273]

Answer:

It's not specific enough, I'll come back to you!

6 0

3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Help me solve (b) in this quadrilateral

Savatey [412]

Answer:

b = 87°

Step-by-step explanation:

In order to answer this question, we need to utilise an important angle fact which is <em>angles in a quadrilateral add up to 360° </em>

Using the information we can set up an equation to find the value of b

→ Form equation

63 + 140 + 70 + b = 360

→ Simplify

273 + b = 360

→ Minus 273 from both sides isolate b

b = 87°

3 0

3 years ago

Read 2 more answers

How many sides has an equiangular polygon if one of its exterior angles is 25 5/7?

lys-0071 [83]

Step One
Figure out the interior angle
25 5/7 = 25.714285 repeating. The interior angle is the supplement of this angle.

180 - 25.714285 = 154.2857
The formula relating the number of sides and the interior equal angle is

interior equal angle = 180 ( 1 - 2/n) where n is the number of sides. (Google equiangular polygon to find this formula.)

154.2857 / 180 = 1 - 2/n)
0.8571428 = 6/7 = 1 - 2/n
1/7 = 2/n
n = 14 sides
This figure is regular as well as equiangular.

6 0

3 years ago

Which graph represents the solution set of the system of inequalities?

Novay_Z [31]

Answer:
(see image)
bottom right image

Explanation:
First try the origin (0,0) to rule out two of the graphs.
3y ≥ x - 9
3(0) ≥ (0) - 9
3 ≥ - 9 yes
3x + y > - 3
3(0) + (0) > - 3
3 > - 3 yes
so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs.
Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa.
Try point (4, 2)
3y ≥ x - 9
3(2) ≥ (4) - 9
6 ≥ - 5 yes
3x + y > - 3
3(4) + (2) > - 3
12 + 2 > - 3
14 > - 3 yes
So the graph is the bottom right one since (4, 2) is included in that shaded region.

4 0

3 years ago