Answer:
5 ) The mass, 6) with lubrication and using surfaces that are not rough
Explanation:
5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.
8)
Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.
![F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons]](https://tex.z-dn.net/?f=F_%7Bf%7D%20%3D%20u%2AN%5C%5Cwhere%3A%5C%5Cu%20%3D%20friction%20coefficient%5C%5CN%20%3D%20normal%20force%20%5BNewtons%5D%5C%5CF_%7Bf%7D%3D%20friction%20force%20%5BNewtons%5D)
Answer:
Power = Current × Voltage
Explanation:
Units:
Power = Watts
Current = Àmperes
Voltage = Volts
Answer:
Explanation:
K = Kinetic energy
= Perigee speed = 4280 m/s
= Apogee speed = 3990 m/s
= Perigee Distance = 22500000 m
= Apogee Distance = 24100000 m
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
M = Mass of Earth
m = Mass of satellite
In this system the kinetic and potential energies are conserved
The mass of the Earth is
Answer:
0° C
Explanation:
Given that
Mass of ice, m = 50g
Mass of water, m(w) = 50g
Temperature of ice, T(i) = 0° C
Temperature of water, T(w) = 80° C
Also, it is known that
Specific heat of water, c = 1 cal/g/°C
Latent heat of ice, L(w) = 89 cal/g
Let us assume T to be the final temperature of mixture.
This makes the energy balance equation:
Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C
m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have
50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)
4000 + 50T = 4000 - 50T
0 = 100 T
T = 0° C
Thus, the final temperature is 0° C
