Answer: star on far side of Andromeda Galaxy- star on near side of Andromeda Galaxy- star on far side of Milky Way Galaxy- star near center of Milky Way Galaxy- Orion Nebula- Alpha Centauri- Pluto-The Sun
Explanation:
Andromeda is the nearest spiral galaxy to our Milky way galaxy. The star on the far side of the Andromeda galaxy would be farthest from Earth. Then, the star at the near side of the Andromeda galaxy.
The Earth along with the Sun and other planets are located in the Orion arm of the Milky way. It is about 8 kpc from the center of the Milky way. Thus, the next farthest astronomical object would be the star on the far side of the milky way and then a star near the center of the Milky way galaxy.
Orion Nebula is 1344 ly away from Earth. Alpha centauri is 4.36 ly away from earth. Pluto is about 28 AU away from Earth and Sun is 1 AU distance away.
Answer: If, enough evidence accumulates to support a hypothesis, it moves to the next step (known as a theory) in the scientific method and becomes accepted as a valid explanation of a phenomenon.
Explanation: a scientific theory is the framework for observations and facts.
( hope this helped )
Answer:
1) v = 7.70 10³ m/s
, 2) F = 115 N and 3) (F/W)% = 90.2%
Explanation:
1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal
F = ma.
F = G m M / r²
a = v² / r
G m M / r² = m v² / r
G M / r = v²
Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth
r = Re + 345 103
r = 6.37 10⁶ + 3.45 10⁵
r = 6.715 10⁶ m
Let's calculate the speed
v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)
v = 7.70 10³ m/s
The speed module is constant, so we can use the uniform motion relationships
v = d / t
The distance is the length of the circle
d = 2π r
d = 2π 6.715 106
d = 42.2 10⁶ m
Let's calculate the time
t = d / v
t = 42.2 10⁶ / 7.70 10³
t = 5.48 10³ s
2) Let's use the universal gravitation equation
F = G m M / r²
F = 6.67 10⁻¹¹ 13.0 5.98 10²⁴ /(6.715 10⁶)²
F = 11.5 10¹ N
F = 115 N
3) in this for we are asked the relationship is out with the weight of the body on earth
F / W = F / mg
F / W = 115 / (13.0 9.8)
F / W = 0.902
F / W% = 90.2%
Answer:
Magnetic energy stored in the inductor when all of the energy in the circuit is in the inductor = 0.049 mJ
If all the energy is then transferred into the capacitor, the voltage drop across the capacitor = 0.00572 V = 0.01 V (expressed to the hundredths value)
Explanation:
In an RLC circuit with maximum current of 7mA = 0.007 A
When all of the energy is stored in the inductor, maximum current will flow through it,
Hence E = (1/2) LI²
L = inductance of the inductor = 2 H
E = (1/2) (2)(0.007²) = 0.000049 J = 0.049 mJ
When all the energy in the circuit is in the capacitor, this energy will be equal to the energy calculated above.
And for a capacitor, energy is given as
E = (1/2) CV²
E = 0.000049 J, C = 3 F, V = ?
0.000049 = (1/2)(3)(V²)
V = 0.00572 V = 0.01 V
Answer:
voltmeter (C. Volts)
Explanation:
The amount of electrical potential is measured by voltmeter. Electrical potential is the amount of work needed to move a unit electric charge from a reference point to the specific point in an electric field. <u>The SI unit of electrical potential is Volt</u>.
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