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3 years ago

ANSWER 5 AND 8!!!!!;$$4$;$;

Physics

1 answer:

DedPeter [7]3 years ago

4 0

Answer:

5 ) The mass, 6) with lubrication and using surfaces that are not rough

Explanation:

5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.

Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.

$F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons]$

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Answer:

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2 years ago

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3 years ago

Read 2 more answers

The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s

notka56 [123]

Answer:

P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

I = P / A

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let's clear the power and replace

P = I A

P = I (4π r²)

let's calculate

P = 5.00 (4π 2²)

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3 years ago

A piece of steel is 11.5cm long at 22C. It is heated to 1221C, close to its melting point. How long is it, in cm, at the high te

Nataly [62]

Answer:

The length at the final temperature is 11.7 cm.

Explanation:

We need to use the thermal expansion equation:

$\Delta L=\alpha L_{0}\Delta T$

Where:

L(0) is the initial length
ΔT is the differential temperature, final temperature minus initial temperature (T(f)-T(0))
ΔL is the final length minus the initial length (L(f)-L(0))
α is the coefficient of linear expantion of steel (12.5*10⁻⁶ 1/°C)

So, we have:

$L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})$