A ticker timer 50dots per second. When a body is pulled by a tap through the timer, the distance between the third and fourth do
t is 3cm and the distance between fourth and fifth dot is 4cm.What is the acceleration of the body?
1 answer:
Answer:
Explanation:
Time for one dot = 1 /50 = .02 s
Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s
velocity = 3 cm / .02 = 150 cm /s
Distance between 4 th and 5 th dot is 4 cm and time taken to travel this distance is .02 s
velocity = 4 cm / .02 = 200 cm /s
change in velocity = 200 cm/s - 150cm/s = 50 cm /s
Time taken = .02 s
Acceleration = 50 / .02 cm/s²
= 2500 cm/s²
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