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vovikov84 [41]
3 years ago
12

A ticker timer 50dots per second. When a body is pulled by a tap through the timer, the distance between the third and fourth do

t is 3cm and the distance between fourth and fifth dot is 4cm.What is the acceleration of the body?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

Explanation:

Time for one dot = 1 /50 = .02 s

Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s

velocity = 3 cm / .02 = 150 cm /s

Distance between 4 th and 5 th  dot is 4 cm and time taken to travel this distance is .02 s

velocity = 4 cm / .02 = 200 cm /s

change in velocity = 200 cm/s  - 150cm/s = 50 cm /s

Time taken = .02 s

Acceleration = 50 / .02 cm/s²

= 2500 cm/s²

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Answer:

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Or maybe sometimes the reader will get confused as there is no name for the two people .

So, i suggest that you should write the names

Explanation:

You can even ask to your class teacher for further clarification

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3 years ago
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A dolphin in an aquatic show jumps straight up out of the water at a velocity of 13.0 m/s.
SVEN [57.7K]

Answer:

a) Knowns, initial speed v_{i}=13.0 m/s, final speed v_{f}=0 m/s and gravity due it is a constant g=9.8m/s^{2}

b) The maximum high reached by the dolphin is y_{max}=8.62 m

c) Total time is t=2.65s

Explanation:

a) First of all the initial speed is given at the start of the problem, gravity is constant and final speed is known any object thrown straight up reaches its max high at 0m/s speed.

b) Second, now that we know final speed we use v_{f} =v_{i}-gt, as we clear for t=\frac{v_{i}-v_{f} }{g}=\frac{20.0m/s}{9.8m/s^{2} }=1.32 s.

Then we use y=v_{i}t-\frac{1}{2} gt^{2}=(20.0m/s)(1.32s)-\frac{1}{2} (9.8m/s^{2} ) (1.32s)^{2}  =8.62m

c)Third, finally we can use y=v_{i}t-\frac{1}{2} gt^{2}, as we know y=0m when the dolphin fall into the water again and v_{i} =13.0m/s, then we have 0=(13m/s)t-\frac{1}{2} (9.8m/s^{2}  )t^{2} is a quadratic form 0=t(13.0-4.9t) so we have t_{i}=0s and t_{f}=\frac{13}{4.90}  =2.65s

6 0
3 years ago
A football player with a mass of 85 kg wears a uniform and helmet that have a mass of 4.5 kg. The football player moves at 2.1 m
DochEvi [55]
The answer would be 187.95 kg.m/s.

To get the momentum, all you have to do is multiply the mass of the moving object by the velocity. 

p = mv

Where:
P = momentum
m = mass
v = velocity

Not the question is asking what is the total momentum of the football player and uniform. So we need to first get the combined mass of the football player and the uniform. 

Mass of football player = 85.0 kg
Mass of the uniform     = <u>  4.5 kg</u>
TOTAL MASS                  89.5 kg

So now we have the mass. So let us get the momentum of the combined masses. 

p = mv
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