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vovikov84 [41]
3 years ago
12

A ticker timer 50dots per second. When a body is pulled by a tap through the timer, the distance between the third and fourth do

t is 3cm and the distance between fourth and fifth dot is 4cm.What is the acceleration of the body?
Physics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

Explanation:

Time for one dot = 1 /50 = .02 s

Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s

velocity = 3 cm / .02 = 150 cm /s

Distance between 4 th and 5 th  dot is 4 cm and time taken to travel this distance is .02 s

velocity = 4 cm / .02 = 200 cm /s

change in velocity = 200 cm/s  - 150cm/s = 50 cm /s

Time taken = .02 s

Acceleration = 50 / .02 cm/s²

= 2500 cm/s²

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15. A volleyball player who weighs 650 Newtons jumps 0.500 meters vertically off the floor. What is her kinetic energy just befo
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<h2>Kinetic energy just before hitting the floor is 324.57 J</h2>

Explanation:

Weight of volleyball player = 650 N

That is

            Mass x Acceleration due to gravity = 650

            Mass x 9.81 = 650

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We also have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 9.81 m/s²  

Final velocity, v = ?

Displacement, s = 0.5 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 9.81 x 0.5

v = 3.13 m/s

Velocity with which he lands on ground is 3.13 m/s

We have kinetic energy = 0.5 x Mass x Velocity²

Substituting

          Kinetic energy = 0.5 x 66.26 x 3.13²

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Kinetic energy just before hitting the floor is 324.57 J

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