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Solnce55 [7]
1 year ago
7

The same book is placed on a table .9m high. What type of energy does it have and how much?

Physics
1 answer:
Lina20 [59]1 year ago
6 0

<em>mass (m)= 5 kg</em>

<em>height (h)= 9m </em>

<em>gravity (g)= 9.8 m/s^2</em>

It has Potential energy. (PE)

• PE = mgh

Replacing:

PE = 5 * 9.8 * 9 = 441 Joules

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What happens to the entropy of a piece of wood as it is burned?
9966 [12]

Answer: Option (a) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness present in a substance. This means that more randomly the atoms in a substance are moving more will be entropy of the substance.

Entropy of a substance increases with increase in temperature.

For example, when a piece of wood is burned then its molecules will gain kinetic energy and hence, they start to move randomly from one place to another.

As a result, there will occur an increase in its entropy.

Thus, we can conclude that when a piece of wood is burned then its entropy increases.

4 0
3 years ago
What happens at the end of most cold currents?​
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Answer:

Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off, thus influencing both weather and climate.

Explanation:

5 0
2 years ago
Read 2 more answers
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 28.0
mel-nik [20]

Answer:

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

w=P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

Also,

Considering the ideal gas equation as:-

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 8.314 J/ K mol

So,

V=\frac{nRT}{P}

Also, for change in volume at constant pressure, the above equation can be written as;-

\Delta V=\frac{nR\times \Delta T}{P}

So, putting in the expression of the work done, we get that:-

w=P\times \frac{nR\times \Delta T}{P}=nR\times \Delta T

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

n = 6 moles

So,

1770\ J=6 moles\times 8.314\ J/ Kmol \times (T_2-301.15\ K)

Thus,

T_2=301.15\ K+\frac{1770}{6\times 8.314}\ K

T_2=336.63\ K

The temperature in Celsius = 336.63-273.15 °C = 63.5 °C

<u>The final temperature is:- 63.5 °C</u>

7 0
3 years ago
20 POINTS WILL BE MARK BRAINLIEST<br><br> ATTACHED BELOW GAS LAW WORKSHEET
german

Explanation:

I will do two of each as examples.

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P = 50.0 kPa

Charles' law says that at constant pressure, the quotient of the initial volume and temperature equals the quotient of the final volume and temperature.

6. V₁ / T₁ = V₂ / T₂

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V = 5.0 L

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7 0
3 years ago
Which type of circuit is shown?
ivann1987 [24]

Answer:

I think it's D. open series circuit .

Explanation:

<em>hope</em><em> it</em><em> helps</em><em> you</em><em>!</em>

7 0
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