To solve this question, let's divide it in parts.
Part 01: "`Product of 7 and the number"
Let's say the unknown number is "a".
So, the product of 7 and "a" is 7a.
Part 02: The sum of -8 and the product of 7 and a number.
Since "the product of 7 and a number" is 7a:
The sum of -8 and 7a is
Answer:
- 8 + 7a
Answer:
Step-by-step explanation:
Circumcenter of A triangle is the center of a circle passing through the vertices of the given triangle.
So, the distance of Z from the vertices Q, R and S will be the radii of the circle.
Therefore, ZQ = ZR = ZS
Since, circumcenter of a triangle is defined by the point of intersection of the perpendicular bisectors of the sides of the given triangle.
Therefore, points W, X and Y are the midpoints of sides QR, RS and QS.
Using these facts,
a). QR = 2(WQ)
= 2(25)
= 50
b). Apply Pythagoras theorem in ΔRXZ,
(RZ)² = (RX)² + (ZX)²
(RZ)² = (40)² + (9)²
RZ = √1681 = 41
c). XS =
=
= 40
d). Since, ZQ = ZR = ZS
ZS = 41
e). By applying Pythagoras theorem in ΔRWZ,
(RZ)² = (WZ)² + (WR)²
(41)² = (WZ)² + (25)²
(WZ)² = (41)² - (25)²
WZ = √1056
WZ =
≈ 32.5
