Look kid, this question has been up for 14 hours think its time to let it go......... hoped i helped. ✔verified✔
Answer:
p = $ 12521.82
Step-by-step explanation:
Interest Rate = 3.6 %, Compounding Frequency: Semi-Annual, Equivalent Annual Interest Rate
%
Number of Repayments is 11 with 10 being equal in magnitude and the last one being worth $ 270, the first repayment comes at the end of Year 2
Let $ p be the level payments that required. Therefore,
![100000 = p\times \frac{1}{0.0363} \times [1-\frac{1}{(1.0363)^{10}}] \times \frac{1}{(1.0363)} + \frac{270}{(1.0363)^{12}}](https://tex.z-dn.net/?f=100000%20%3D%20p%5Ctimes%20%20%5Cfrac%7B1%7D%7B0.0363%7D%20%5Ctimes%20%5B1-%5Cfrac%7B1%7D%7B%281.0363%29%5E%7B10%7D%7D%5D%20%5Ctimes%20%5Cfrac%7B1%7D%7B%281.0363%29%7D%20%2B%20%5Cfrac%7B270%7D%7B%281.0363%29%5E%7B12%7D%7D)
100,000 - 176.01 = p x 7.972
p = $ 12521.82
Answer:
Step-by-step explanation:
In a geometric sequence, the nth term is
T_n = ar^(n-1)
a = first term
r = common ratio which can be gotten by dividing second term by first term, third term by second term etc
Therefore
a = 16
r = -3.2 ÷ 16
r = -0.2
T_7 = ar^(7-1)
T_7 = ar^6
T_7 = 16[(-0.2)^6]
T_7 = 16(0.000064)
T_7 = 0.001024
Answer:
B. Each value has its own f(x)=y
Answer:
3 min
Step-by-step explanation:
because on monday 2
and on tuesday is 1 so
1 plus 2
equals 3