Answer:
21 matches
Step-by-step explanation:
This is a combination problem where we have to select two member out of 7 members
So we want calculation of 7C2
7C2 = 7!/[(2!)(7-2)!]
(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]
(7*6)/2 ~ Note everything that easily cancels here!
42/2
21 matches
4/10 × 1/6 = 2/30
You can cross cancel 4 and six...then multiply 2/10 × 1/3 which equals 2/30
If you want you can simplify 2/30 to 1/15
3/4 (x-12)=12
3/4x - 9= 12
+9 +9
3/4x=21
*3/4 *3/4
x= 15 3/4
and
3/4y-12=12
+12 +12
3/4y = 24
*3/4 *3/4
y= 18
20^2 + 21^2 = 27^2
400 + 441 = 729
881 = 729 (does not equal)
Not a right traingle