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3 years ago

Please help me asap.Explain by showing please.

Mathematics

1 answer:

quester [9]3 years ago

3 0

I'm sorry I would help but I'm going to have to say b sorry for not being able to show

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Solve the equation 16=9+x

vitfil [10]

Answer:

x = 7

Step-by-step explanation:

9 get subtracted on both sides and then 16-9 is 7

5 0

3 years ago

Read 2 more answers

Select all expressions that are equivalent to 5x + (x+6) +3x.

zhuklara [117]

Answer:

9x + 6 and 6x + 6 + 3x

Step-by-step explanation:

6 0

2 years ago

#20 four times the sum of number. and 15 is a least20. Let X represent the number. :find ball possible values for X

gayaneshka [121]

For this case what we have to take into account is the following variable:
x = represent the unknown number
We now write the following inequality:
"four times the sum of number and 15 is at least 20"
4 (x + 15)> = 20
We clear the value of x:
(x + 15)> = 20/4
(x + 15)> = 5
x> = 5 - 15
x> = - 10
The solution set is:
[-10, inf)
Answer:
all possible values for X are:
[-10, inf)

6 0

3 years ago

Let 2004-02-01-02-00_files/i0200000.jpg. If 2004-02-01-02-00_files/i0200001.jpg is a complement of 2004-02-01-02-00_files/i02000

Reika [66]

Answer: The answer is (C) 180°.

Step-by-step explanation: Given that m∠A = 40°. ∠B is a complement of ∠A and ∠C is a supplement of ∠B. We are to find m∠B + m∠C.

Since ∠B is a complement of ∠A, so we have

$m\angle A+m\angle B=90^\circ\\\\\Rightarrow m\angle B=90^\circ-m\angle A=90^\circ-40^\circ\\\\\Rightarrow m\angle B=50^\circ.$

Now, since ∠C is a supplement of ∠B, so we have

$m\angle B+m\angle C=180^\circ\\\\\Rightarrow m\angle C=180^\circ-m\angle B=180^\circ-50^\circ\\\\\Rightarrow m\angle C=130^\circ.$

Therefore,

$m\angle B+m\angle C=50^\circ+130^\circ=180^\circ.$

Thus, (C) is the correct answer.

7 0

3 years ago

Read 2 more answers

A pedestrian walks 7.4 kilometers west

attashe74 [19]

Answer: 11.8 km

Step-by-step explanation:

The resulting figure is a right angled triangle shown below

$Apply the Pythagorean theorem to find out the magnitude of the resultant vector $A B$ in the triangle $A B C$ as follows -$$\begin{aligned}&A B^{2}=B C^{2}+C A^{2} \text { (Hypotenuse }{ }^{2}=\text { Base }^{2}+\text { Adjacent }^{2} \text { ) } \\&=7.4^{2}+9.2^{2} \\&=139.4 \\&A B=11.806777 \\&\quad A B \approx 11.8 \mathrm{~km} \text { (Rounded off to the nearest tenth) }\end{aligned}$

3 0

2 years ago