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prohojiy [21]
4 years ago
9

Simplify 4y+6x-3(x-2y)​

Mathematics
2 answers:
STALIN [3.7K]4 years ago
8 0

Answer:

 10y + 3x

Step-by-step explanation:

 (4y + 6x) -  3 • (x - 2y)

AveGali [126]4 years ago
8 0

Answer:

I think it's 10y+3x

Step-by-step explanation:

I search it up :(

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Find two numbers whose sum is 44 and whose difference is 20 (PLEASE HELP I HAVE 5 MINUTES)
vova2212 [387]
The correct answers would be 32 and 12.
32 + 12 = 40, and 32 - 12 = 20. Hope this helps! Have a great day!
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A carpet costs $15 per square foot. If the area you want to carpet is 19.7 square meters, how much will it cost to buy the carpe
EleoNora [17]
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5 0
3 years ago
Your company is considering offering 900 employees the opportunity to transfer to its new headquarters in Ottawa and, as personn
Tresset [83]

Answer:

a) P(100M) = \frac{100C100*1100C800}{1200C900}

b) P(1M) = \frac{100C1*1199C899}{1200C900}

Step-by-step explanation:

Extract information from question:

Manager = M = 100

Factory Workers = FW = 200

Miscellaneous Staff = MS = 900

Total Workers = 1200

Moving Workers = 900

'Combinations' are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations the formula below is used:

nCr=\frac{n!}{r!(n-r)!}

where 'n' is the total number of items

'r' is the number of items being chosen at a time

The '!' is the factorial function which is the product of all integers equal to and less than the given integer.

Combinations can be calculated manually using the formula above or by using the nCr function on a scientific calculator.

Part a)

Combinations of all 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(100M) = 100C100

Combinations of 800 of factory workers and miscellaneous staff being selected out of 1100 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(800FW/MS) = 1100C800

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of all 100 managers being selected:

P(100M) = \frac{100C100*1100C800}{1200C900}

Part b)

Combinations of 1 out of 100 managers being selected

C = nCr=\frac{n!}{r!(n-r)!}

C(1M) = 100C1

Combinations of 899 of managers, factory workers and miscellaneous staff being selected out of 1199 remaining staff

C = nCr=\frac{n!}{r!(n-r)!}

C(899M/FW/MS) = 1199C899

Total possible unspecified combinations of 900 staff being selected out of 1200 total staff

C = nCr=\frac{n!}{r!(n-r)!}

C(900M/FW/MS) = 1200C900

Probability of being the 1 manager being selected:

P(1M) = \frac{100C1*1199C899}{1200C900}

3 0
3 years ago
A class includes 20 students. Eight of them got A+ on the last test. What percent of the class got A+?
alekssr [168]

Answer:

40%

Step-by-step explanation:

8/20

2/5

2/5 = 40%

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

3 0
3 years ago
What is the volume of this cone -radius 4ft, height of 8?
erastova [34]

Answer:

V= 134.04 ft³

Step-by-step explanation:

7 0
3 years ago
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