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ololo11 [35]
3 years ago
10

Which of the following is the result of the operation below?

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

The result of the operation is:

\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right]

Step-by-step explanation:

The matrix provided is:

\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right]

The operation to be performed is:

-R_{1}+R_{2} → R_{2}

The operation implies that, we need to replace the values in row 2 by the result of the expression (-R_{1}+R_{2}).

Complete the operation as follows:

\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right]\rightarrow \ \left[\begin{array}{ccc|c}1&2&3&6\\(-1+1)&(-2+1)&(-3+1)&(-6-2)\\0&2&1&5\end{array}\right]

                            \rightarrow\ \left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right]

Thus, the result of the operation is:

\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right]

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cestrela7 [59]

Answer:

$12,415.48

Step-by-step explanation:

A = P (1 + r/n)^(nt)

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Answer:

Step-by-step explanation:

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2 years ago
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Hope this helps!
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