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elena55 [62]
3 years ago
8

How do I factor 8x^4-48x^3=56x^2

Mathematics
2 answers:
shusha [124]3 years ago
8 0
8x^4-48x^3=56x^2 \\ \\ 8x^4-48x^3-56x^2=0 \\ \\ \boxed{8x^2(x^2-6x-7)=0}
maria [59]3 years ago
5 0
8x^4-48x^3=56x^2\\
Assumption\ x \neq 0\\\\
8x^4-48x^3=56x^2\ \ \ |Divide\ by\ x^2\\\\
8x^2-48x=56\ \ \ |Subtract\ 56\\\\
8x^2-48x-56=0\ \ |Divide\ by\ 8\\\\
x^2-6x-7=0\\\\
x^2-7x+x-7=0\\\\
x(x-7)+1(x-7)=0\\\\ \textbf{Factorised:(x-7)(x+1)=0}\\
\textbf{x=7\ \ or\ \ x=-1}

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We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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The required factors are - 32 and - 9

Use these factors to split the x- term

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Step-by-step explanation:

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first piece is 1.25 meters long

second piece will be (4-1.25)=2.75 meters long

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