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atroni [7]
2 years ago
8

Given the function f ( x ) = 5 + x 2 , calculate the following values:

Mathematics
1 answer:
Drupady [299]2 years ago
7 0

Answer:

f(x+1)=<em>fx+f</em>

<em>f(x)+f(6)=fx+6f</em>

<em />

Step-by-step explanation:

You might be interested in
Factor the expression x2 – 9x + 14
Anna [14]
X² - 9x + 14
x² - 2x - 7x + 14
x (x - 2) -7 (x - 2)
x - 7 =0  OR  x - 2 = 0
x = 7  OR  x = 2

In short, Your Roots would be 2 & 7

Hope this helps!
7 0
3 years ago
Read 2 more answers
What are the Ratio 4:5 and 8:10?
miv72 [106K]

Answer:

4/5 = 80% and 8/10 = 80%

Step-by-step explanation:

3 0
3 years ago
Kerri and James practiced for the school track meet. Kerri completed 8 laps in 16 minutes. If James ran at the same rate, how ma
katrin [286]

Answer:

it took him 10 mintues to run 5 laps

Step-by-step explanation:

6 0
3 years ago
Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
3 years ago
PLEASE HELP!!
Sergeeva-Olga [200]

Answer:

and the addition will be p+q

Step-by-step explanation:

the diffrence between p and q is u have to add so the answer will be p-q

7 0
3 years ago
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