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atroni [7]
3 years ago
8

Given the function f ( x ) = 5 + x 2 , calculate the following values:

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

f(x+1)=<em>fx+f</em>

<em>f(x)+f(6)=fx+6f</em>

<em />

Step-by-step explanation:

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ivolga24 [154]
It is 1024 i believe. 16^3/4 = 1024
3 0
3 years ago
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Tiffany answered 80% of the questions on her math test correctly. There were 40 questions. How many questions did Tiffany get co
Harlamova29_29 [7]
Tiffany answered 32 questions correctly since 32/40 is .80
7 0
4 years ago
A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.If the mixture is to be made from milk containing
3241004551 [841]

Answer:

<u>800 pints</u> of 5% butterfat and <u>200 pints</u> of 20% butterfat is needed.

Step-by-step explanation:

Given:

A dairy wishes to mix together 1,000 pints of milk that contains 8% butterfat.

If the mixture is to be made from milk containing 5% butterfat, and cream

containing 20% butterfat.

Now, to find the pints of each is needed.

Let the pints of 5% butterfat be x.

And the pints of 20% butterfat be y.

<em>So, the total pints of milk:</em>

x+y=1000

x=1000-y  ......(1)

<em>As, given:</em>

<em>1,000 pints of milk that contains 8% butterfat.</em>

<em>The mixture of milk containing 5% butterfat, and cream containing 20% butterfat.</em>

According to question:

5(x)+20(y)=8(1000)

5x+20y=8000

Substituting the value of x from equation (1):

5(1000-y)+20y=8000

5000-5y+20y=8000

5000+15y=8000

<em>Subtracting both sides by 5000 we get:</em>

15y=3000

<em>Dividing both sides by 15 we get:</em>

y=200.

<em>The pints of 20% butterfat = 200 pints.</em>

Now, to get the pints of 5% butterfat we put the value of y in equation (1):

x=1000-y

x=1000-200

x=800.

<em>The pints of 5% butterfat = 800 pints.</em>

Therefore, 800 pints of 5% butterfat and 200 pints of 20% butterfat is needed.

8 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Elan Coil [88]

Answer:

see explanation

Step-by-step explanation:

The diagrams show triangular figures

The first figure has 1 dot

The second has 1 + 2 = 3 dots

The third has 3 + 3 = 6 dots

The fourth has 6 + 4 = 10 dots

Note the pattern is + 2 , + 3, + 4

Thus the fifth pattern is 10 + 5 = 15 dots

5 0
3 years ago
3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters
Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values.                       a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___  ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_<u>4</u>_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with  3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_<u>4</u>_ <u>_3_</u> ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_<u>4</u>_ _<u>3</u>_ _<u>2</u>_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

8 0
3 years ago
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