The answer is carbon dioxide
Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
![\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3Dmolarity%5Ctimes%20%7B%5Ctext%20%7BVolume%20in%20L%5D%7D%3D0.417M%5Ctimes%200.528L%3D0.220moles)
The balanced chemical equation is:
is the limiting reagent as it limits the formation of product and 
is in excess.
According to stoichiometry :
2 moles of give = 1 mole of 
Thus 0.220 moles of give=
of
Mass of 
Thus 50.7 g of will be formed.
Answer:
For pH= 4.00 :
Add 0.1 ml of 0.1 molar NaOH to 50 ml of 0.1 molar potassium hydrogen phthalate .
<span>The formation of a derivative being a necessary step in the experiment lies in the importance of the derived structure. Often the derived product confers to reaction pathways which uses less reactive starting materials and more easily proceeds to completion. This also allows us to take a small amount of sample. The derived product at times is a general compound allowing its easy analysis. Often we encounter a product but we find it difficult to analyse it in ways we want. Here lies the essence of forming a derivative which often are simpler compounds allowing easier analysis yet having similar functional groups and structural properties. Also sometimes we encounter problems when our desired product is unstable and forms stable degraded products. But if we somehow manage to synthesize a derivative it may be relatively stable and form no degradation products. It would be stable at least for a significant period of time making it easier to study its properties. The derived product also at times are synthesized using general reaction pathways facilitating a way of easier synthesis and helping it to correlate with other similar reaction pathways and products.So the above paragraph accounts for the need of derivatives. When we encounter problems similar to those mentioned above it becomes necessary for a researcher to form rather synthesize a derivative.</span>
I do not know i am doing this for the points
