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4 years ago

The volume of a gas varies inversely with pressure is the definintion of _____.

Chemistry

1 answer:

Ira Lisetskai [31]4 years ago

4 0

The volume of a gas varies inversely with pressure is the definition of Boyle's Law.

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How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t

ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

= 2.75 x 10²³ molecules XeF₆.

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3 years ago

Which best describes a scientist who solves a new problem using something already learned?

adelina 88 [10]

Answer:

The answer should be Skeptical

6 0

3 years ago

What is a good sentence for the word orbit?

seropon [69]

All of the planets orbit around the sun, due to the gravitational pull of the sun

4 0

4 years ago

Read 2 more answers

Someone explain it plz

timofeeve [1]

Answer:

1). 1 mole of Carbon burnt in air

C + O2 →CO2

1 mole of carbon produces 1 mole of CO2 which is 44g of CO2

2). 1 mole of carbon is burnt in 16g of dioxygen

32g of O2 = 44g of CO2

1g of O2 = 44/32

CO2 (Dioxygen is limiting reagent)

16g of O2 = 4/32 × 16 = 22g of CO2 in one mole

3) 2 moles of Carbon burnt in 16g of dioxygen

16g of dioxygen is available, and thus it can combine with 0.5 mol of carbon to give 22g of CO2

4 0

3 years ago

Read 2 more answers

Calculate the volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

gtnhenbr [62]

535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given:

$C(s) + O_2(g)$ ⇒ $CO_2(g)$

1 mole of $CO_2(g)$ is formed from 1 mole of charcoal, that means 1 mole of $CO_2(g)$ is formed from 12 g of charcoal.

1 lbs = 453.592 grams

6.75 lbs = 6.75 x 453.592 =3061.746g

So, $CO_2(g)$ formed from 3061.746g of charcoal is:

= $\frac{1}{12}$ x 3061.746g

=255.14 mol.

Now, at STP, the volume of 1 mol of gas =22.4 L

Volume of 255.14 mol of $CO_2(g)$ = 255.14 x 22.4 L

Volume of 255.14 mol of $CO_2(g)$ = 535.8 L

Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

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2 years ago