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2Na2SO4 :How many atoms for each element are in the formula?<br><br> S=<br> O=<br> Na=

yuradex [85]

Answer:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

Explanation:

The given compound is:

2Na₂SO₄

An element is a distinct substance that cannot be split up into simpler substances.

So;

Number of atoms of elements here are:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

6 0

2 years ago

Give the name and formula of the compound formed from the following elements:<br> (b) ₃₀L and ₁₆M

madam [21]

When sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

<h3>Name of the elements</h3>

The names of the elements that make up the compound will be determined from the atomic mass of the elements.

<h3>Which element has atomic number 30</h3>

The element that atomic number of 30 is zinc and it has oxidation number of +2.

<h3>Which element has atomic number 16</h3>

The element that atomic number of 16 is sulfur and it has oxidation number of -2.

<h3>Chemical reaction between sulfur and zinc metal</h3>

Zn²⁺ + S²⁻ --------> ZnS

Thus, when sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

Learn more about zinc sulfide here: brainly.com/question/20806552

#SPJ1

8 0

1 year ago

An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam

MAXImum [283]

Explanation:

The given data is as follows.

Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence, moles of NaOH in 97 ml = $\frac{0.1090 \times 97}{1000}$

= $10.573 \times 10^{-3} mol$

Moles of HCl in 21.00 ml = $\frac{0.2060 \times 21}{1000}$

= $4.326 \times 10^{-3}$ mol

Therefore, total moles of NaOH that reacted are as follows.

$10.573 \times 10^{-3} mol$ - $4.326 \times 10^{-3} mol$

= $6.247 \times 10^{-3}$ mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

$\frac{6.247 \times 10^{-3}}{3}$

= $2.082 \times 10^{-3}$ mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

$2.082 \times 10^{-3} mol \times 40 g/mol$

= $83.293 \times 10^{-3}$ g

= 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore, 40 g NaOH = 122 g benzoic acid

So, 0.0832 g NaOH = $\frac{122 g}{40 g} \times 0.0832 g$

= 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

$\frac{0.253 g}{0.3471 g} \times 100$

= 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0

3 years ago

How many moles are in 20 grams of argon

Sladkaya [172]

Answer:

There are 0.5 mole in 20g of argon.

Explanation:

40 g of argon = 1mole

Then 20g of argon is,

→ 1/40 × 20

→ 0.5 mole

5 0

2 years ago

Which statements are scientific statements

Harrizon [31]

Wym there is no question or statements.

6 0

3 years ago