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Arlecino [84]
3 years ago
8

The rate law for a reaction is rate=k[A][B] Which one of the following statements is false? The rate law for a reaction is Which

one of the following statements is false? If [A] is doubled, the reaction rate will increase by a factor of 2. The reaction is first order overall. k is the reaction rate constant. The reaction is first order in [B]. The reaction is first order in [A].
Chemistry
1 answer:
Andrews [41]3 years ago
3 0

Answer: The reaction is first order overall.

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

y =1=  order with respect to B

n =( x+y)= (1+1) = 2 = Total order

a)  If [A] is doubled, the reaction rate will increase by a factor of 2: True

Rate'=k[2A]^1[B]^1

Rate'=k[2]^1[A]^1[B]^1

Rate'=[2]^1\times Rate

Rate'=[2]\times Rate

b) The reaction is first order overall: False

The overall order is 1+1= 2.

c)  k is the reaction rate constant: True

Rate=k[A]^x[B]^y

k= rate constant

d) The reaction is first order in [B]: True

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

e) The reaction is first order in [A]: True

For the given rate law:

Rate=k[A]^1[B]^1

y =1=  order with respect to B

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7 0
4 years ago
Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
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