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Arlecino [84]
3 years ago
8

The rate law for a reaction is rate=k[A][B] Which one of the following statements is false? The rate law for a reaction is Which

one of the following statements is false? If [A] is doubled, the reaction rate will increase by a factor of 2. The reaction is first order overall. k is the reaction rate constant. The reaction is first order in [B]. The reaction is first order in [A].
Chemistry
1 answer:
Andrews [41]3 years ago
3 0

Answer: The reaction is first order overall.

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

y =1=  order with respect to B

n =( x+y)= (1+1) = 2 = Total order

a)  If [A] is doubled, the reaction rate will increase by a factor of 2: True

Rate'=k[2A]^1[B]^1

Rate'=k[2]^1[A]^1[B]^1

Rate'=[2]^1\times Rate

Rate'=[2]\times Rate

b) The reaction is first order overall: False

The overall order is 1+1= 2.

c)  k is the reaction rate constant: True

Rate=k[A]^x[B]^y

k= rate constant

d) The reaction is first order in [B]: True

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

e) The reaction is first order in [A]: True

For the given rate law:

Rate=k[A]^1[B]^1

y =1=  order with respect to B

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Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
3 years ago
How many moles are in 2.8x10^23 atoms of Calcium?
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X mole ➡️ 2.8×10²⁴ atoms of si.

X = 2.8×10×10²³/6.022×10²³

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Explanation:

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The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.

The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.

Learn more: brainly.com/question/22824409

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