Stoichiomety:
1 moles of C + 1 mol of O2 = 1 mol of CO2
multiply each # of moles times the atomic molar mass of the compund to find the relation is weights
Atomic or molar weights:
C: 12 g/mol
O2: 2 * 16 g/mol = 32 g/mol
CO2 = 12 g/mol + 2* 16 g/mol = 44 g/mol
Stoichiometry:
12 g of C react with 32 g of O2 to produce 44 g of CO2
Then 18 g of C will react with: 18 * 32/ 12 g of Oxygen = 48 g of Oxygen
And the result will be 12 g of C + 48 g of O2 = 60 g of CO2.
You cannot obtain 72 g of CO2 from 18 g of C.
May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
I believe that the answer is D.
I hope this helps. :)
<h3>
Answer:</h3>
Temperature is 529.164 K
<h3>
Explanation:</h3>
We are given
Number of moles of Ne (n) = 0.019135 moles
Volume (V) = 878.3 mL
Pressure (P) = 0.946 atm
We are required to calculate the temperature;
We can do this using the ideal gas law equation which is;
PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.
From the equation;
Therefore, the temperature will be 529.164 K.
Answer:
True
Explanation:
Well,I hope it helps....
Just correct me if I'm wrong..
