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2 years ago

Given below are descriptions of two lines.

Mathematics

1 answer:

gulaghasi [49]2 years ago

5 0

Answer:

Line 1 is 1/3

Line 2 is 1/3 as well

Choice 1

Step-by-step explanation:

Rise over run

Line 1:

$\frac{(7)-(3)}{(6)-(-6)}$

$\frac{4}{12}$

Simplify:

1/3

Line 2:

$\frac{(2)-(1)}{(-3)-(-6)}$

$\frac{1}{3}$

1/3

1 is Paralell to 2 because they have the same slope

I hope this helps! :D

Pls give thx and brainliest if i’m right!

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SOMEONE HELP WITH THIS PLZZ!!

Natali5045456 [20]

Answer:

x=90 y=45

Step-by-step explanation:

Answer is C

y and 45 are vertical angles

x=90 (right angle)

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2 years ago

As an estimation we are told 5 miles is 8 km. Convert 24 km to miles.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

24*5=120 / 8 = 15

15 is answer.

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2 years ago

Find the volume thank you for the help

Sergeeva-Olga [200]

Answer:

all you need to do is multiply length times width times height.

Step-by-step explanation:

5 1/2 x 3= 16.5

16.5 x 2 1/4= 453.75

now just add both answers :)

I really hope this helps! <3 Good luck!

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2 years ago

A school has 400 students. They all come to school by bus, and each bus carries the same number of students. How many students m

Ainat [17]

Depends. All multiples of 400, you could have many different options. For example, 400 buses 1 kid on ea. 40 buses 10 kids on ea.

400x1=400
40x10=400

Just if the two numbers multiple to 400 it can be an answer

8 0

2 years ago

Read 2 more answers

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

5 0

2 years ago