Question

a flat bed truck is carrying a crate up a 10.0 hill inn the picture. the coefficent of the static friction between the truck bed and the crate is u=0.25. find the maximum acceleration

Answer 1

Answer:

$a = 0.711 m/s^2$

Explanation:

As we know that truck is moving up the hill

So here we have two forces on the crate placed on the truck

1) gravitational force along the floor

2) Friction force along the floor

Now here if the truck is moving with maximum possible acceleration so that there is no slipping of the crate

So here we will have

$\mu mg cos\theta - mgsin\theta = ma$

$a = \mu g cos\theta - g sin\theta$

$a = (0.25)(9.81)cos10 - 9.81 sin10$

$a = 0.711 m/s^2$