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Angelina_Jolie [31]
4 years ago
7

The neck is a

Physics
2 answers:
skad [1K]4 years ago
7 0
The answer would be first class lever

ad-work [718]4 years ago
6 0

Answer:

a) first class lever

You might be interested in
Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
Vadim26 [7]

Heya!!

For calculate aceleration, let's applicate second law of Newton:

\boxed{F=ma}

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

12\ N = 3\ kg * \textbf{a}

\textbf{a} = 12\ N / 3\ kg

\textbf{a} = 4\ m/s^{2}

Result:

The aceleration of the object is of <u>4 m/s²</u>

3 0
3 years ago
What is the radius of a circle thats the diameter of 480?
Luda [366]
The answer is 12.36. hoped this helped!
4 0
3 years ago
A 5 kg
kotykmax [81]

Answer:

<em>The object-Earth system is open</em>

F_n=ma=5\ (7.2)=36\ N

Explanation:

<u>Accelerated Motion </u>

When an object is released in free air (with no other forces than the gravity), it describes a free-fall motion and the formulas include the acceleration of gravity as part of the calculations. But when there is another external force, then the acceleration is not the gravity, but the result of the net force exerted on the mass of the object.

By definition, an open system includes the exchange of energy from and to the surroundings, that is why all systems surrounding our planet are considered as open systems. In our case, the object is interacting with the planet's gravity and there is some other external force, which will be computed later. The object-Earth system is open.

If the object starts from rest, its initial speed is zero, and

v_f=a\ t

where a is the acceleration and t is the time. The distance traveled is given by :

\displaystyle y=\frac{a\ t^2}{2}

From the two above equations, we find that:

v_f^2=2ay

Solving for a

\displaystyle a=\frac{v_f^2}{2y}

\displaystyle a=\frac{12^2}{2\ (10)}

a=7.2\ m/s^2

It means the net force is

F_n=ma=5\ (7.2)=36\ N

The object's weight is

W=5\ (9.8)=49 N

This means there is some external force acting upwards delaying the object's fall of a magnitude of

F_e=49-36=13\ N

3 0
3 years ago
A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using co
timurjin [86]

Answer:

mgh =  \frac{1}{2} m {v}^{2}  \\ v =  \sqrt{2gh}  \\  =  \sqrt{2 \times 9.8 \times 10}  \: m. {s}^{ - 1}

5 0
3 years ago
A ball with a mass of 500g is lifted to a shelf 2 meter above ground. Calculate for the gravitational potential energy gained by
wariber [46]

Givens

  • 500 grams = 500 grams * [1 kg/1000 grams] = 0.5 kg
  • h = 2 meters
  • g = 9.81

Formula

PE = m*g*h

Solution

PE = 0.5 * 9.81 * 2

PE = 9.81 Joules


7 0
3 years ago
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