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Sergio [31]
3 years ago
14

Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on Susa

n? A) The net force acting on the runner must be zero. Eliminate B) The net force depends on the pull of gravity on the runner. C) The net force acting on the object is pushing in the same direction the object is traveling. D) The net force acting on the object is pushing in the opposite direction the object is traveling.
Physics
2 answers:
IgorC [24]3 years ago
6 0

Answer:  A) The net force acting on the runner must be zero.

Explanation: i got the question & answer from usatestprep ..

kiruha [24]3 years ago
3 0

Option (A ) is correct.

Explanation:

susan is moving with constant velocity, so both the direction and magnitude of the velocity remains same. so the acceleration of susan =0. This is because an object gets accelerated when either the magnitude or direction of the speed changes.

now the force is given by

F= ma

F= force

m= mass

a= acceleration

Here a =0

so F= 0

so the net force on susan is zero.

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pychu [463]
2 is the answer have a nice day <3
5 0
3 years ago
How much work is done on an object that is moved to acquire a displacement of 5 meters when 500 Newtons of force was exerted?​
grandymaker [24]

Answer:

2,500 Joules (J) or Newton Meter (N M)

Explanation:

Work = Force x Distance

The force in this equation is 500 Newtons. The distance (displacement) is 5 meters. Plug it into the equation above.

Work = 5m x 500n

Work = 2,500 Joules or Newton-Meters.

Therefore 2,500 Joules or Newton Meters of work is done on an object.

3 0
3 years ago
If you run 40 meters in 60 seconds what is your average speed
Vikentia [17]
1.49 MPH (Miles Per Hour)
8 0
3 years ago
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Two vectors pointing right starting at the same position. Vector A is on top and longer. Vector B is shorter and below.
Oksana_A [137]

Answer:

The displacements are not equal. While their direction is the same, their length (i.e., distance or magnitude) is not. A is longer than B.

Explanation:

correct on e2020- sample respnse

4 0
3 years ago
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Katarina [22]

Explanation:

Taking the incident light to be traveling in the + x-direction so that it is at normal incidence to the left side of the film(referred to as the "Front side"). This means the beam transmitted into the liquid is essentially as strong as the incident beam.

Almost all the light that is reflected off the back surface will get through the front surface. (But only 2.78% gets re-reflected off the the front surface back to the right) this means that there are two beams reflected to the - x-direction, one from the front surface and one from the back, and these beams are of almost equal intensity.

Hope this is helpful. Thanks

7 0
3 years ago
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