Answer:
1.429*10^-5 m
Explanation:
From the question, we are given that
Diameter of the cable, d = 3 cm = 0.03 m
Force on the cable, F = 2 kN
Young Modulus, Y = 2*10^11 Pa
Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²
The fractional length = Δl/l
Δl/l = F/AY
Δl/l = 2000 / 0.0007 * 2*10^11
Δl/l = 2000 / 1.4*10^8
Δl/l = 1.429*10^-5 m
Therefore, the fractional length is 1.429*10^-5 m long
Answer:
13.52 Ω
Explanation:
coefficient of thermal resistance be α
R₀ , R₂₅ , R₉₀ and R₋₃₂ be resistances at 0 , 25 , 90 , and - 32 degree
R₂₅ = R₀ + α x 25
R₉₀ = R₀ + α x 90
R₉₀ - R₂₅ = 65 x α
α = (R₉₀ - R₂₅ )/ 65
= (14.55 - 14) / 65
= .55 / 65 Ω per °C,
R₂₅ = R₀ + α x 25
14 = R₀ + (.55 / 65 )x 25
= R₀ + .2115
R₀ = 13.7885 Ω
R₋₃₂ = R₀ - α x 32
= 13.7885 -( .55 / 65) x 32
= 13.7885 - .27077
= 13.51773 Ω
= 13.52 Ω
Answer:
Work done, W = 0.0219 J
Explanation:
Given that,
Force constant of the spring, k = 290 N/m
Compression in the spring, x = 12.3 mm = 0.0123 m
We need to find the work done to compress a spring. The work done in this way is given by :
W = 0.0219 J
So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.
Answer:
The diagram assigned B
explanation:
Check the direction of the two vectors, their resultant must be in the same direction.
