The compound co2 is an example of a(n) atom element ionic compound covalent compound

Why is your physical and mental health important?

Alex73 [517]

Answer: Mental health and physical health are very closely connected. Mental health plays a major role in your ability to maintain good physical health. Mental illnesses, such as depression and anxiety, affect your ability to participate in healthy behaviors.

Explanation: Hope this helped. Have a great day!!!!

4 0

3 years ago

Read 2 more answers

You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a ci

andriy [413]

Answer:

The magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.

Explanation:

Given;

Radius of circular loop, R = 3.00 cm = 0.03 m

Current in the loop, I = 12.0 A

Magnetic field at the center of circular loop is given as;

B = μ₀I / 2R

Where;

μ₀ is constant = 4π x 10⁻⁷ T.m/A

R is the radius of the circular loop

I is the current in the loop

Substitute the given values in the above equation and calculate the magnitude of the magnetic field;

B = (4π x 10⁻⁷ x 12)/ 0.03

B = 5.0272 x 10⁻⁴ T

Therefore, the magnitude of the magnetic field B at the center of the loop is 5.0272 x 10⁻⁴ T.

8 0

3 years ago

A person is standing on an elevator initially at rest at the first floor of a high building. The elevator then begins to ascend

GREYUIT [131]

Answer:

The found acceleration in terms of h and t is:

$a=\frac{h}{5(t_1)^2}$

Explanation:

(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)

We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.

<h3></h3><h3>Stage 1</h3>

Constant acceleration, starts from rest.

Distance = $y = \frac{1}{2}a(t_1)^2$

Velocity = $v_1=at_1$

<h3>Stage 2</h3>

Constant velocity where

Velocity = $v_o=v_1=at_1$

Distance =

<h3> $y_2=v_2(t_2)\\\text{Where~}t_2=4t_1 ~\text{and}~ v_2=v_1=at_1\\y_2=(at_1)(4t_1)\\y_2=4a(t_1)^2\\$ </h3><h3 /><h3>Stage 3</h3>

Constant deceleration where

Velocity = $v_0=v_1=at_1$

Distance =

$y_3=v_1t_3-\frac{1}{2}a(t_3)^2\\\text{Where}~t_3=t_1\\y_3=v_1t_1-\frac{1}{2}a(t_1)^2\\\text{Where}~ v_1t_1=a(t_1)^2\\y_3=a(t_1)^2-\frac{1}{2}a(t_1)^2\\\text{Subtracting both terms:}\\y_3=\frac{1}{2}a(t_1)^2$