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Nikitich [7]
3 years ago
15

If gravity is the only force acting on you, why aren't you moving down right now?

Physics
2 answers:
emmasim [6.3K]3 years ago
6 0

Answer:

gravity holds you down, floors protect that

Explanation:

sammy [17]3 years ago
4 0

Answer: Because the force of gravity depends on the size of the planet, so a smaller planet will have less gravitational force than a larger planet. So our gravitational force is not as strong as a bigger planet so we can still stand up and jump normally but on a smaller planet we could jump higher and on a bigger planet, we could not even be able to jump at all.

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If you are driving 128.4 km/h along a straight road and you look down for 3.0s, how far do you travel during this inattentive pe
ser-zykov [4K]

Answer:

107 m

Explanation:

Convert km/h to m/s:

128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s

Distance = rate × time

d = 35.67 m/s × 3.0 s

d = 107 m

8 0
3 years ago
He distance between two consecutive crests is 2.5 meters. Which characteristic of the wave does this distance represent? amplitu
kupik [55]

Frequency is measured in units of reciprocal time.
Period is measured in units of time.
Phase is a number without units that represents a fraction of a wave.

None of these is measured in meters, so none of them can be the answer.
It must be either amplitude or wavelength.

Amplitude is a quantity that's measured at one or two points in the same wave.
The question is talking about points on consecutive waves.

<em>Wavelength is</em> the only choice left.  That must be it.

3 0
3 years ago
Read 2 more answers
Average velocity is different than average speed because calculating average velocity involves
Artemon [7]

Answer:

calculating displacement.

Explanation:

It's not true that displacement and distance would be the same always. Displacement is always smaller than or equal to distance as it is the smallest path between the initial and final point whereas distance is the measure of the total path covered.

8 0
2 years ago
A 3-m-high, 7-m-wide rectangular gate is hinged at the top edge and is restrained by a fixed ridge. Determine the hydrostatic fo
Shalnov [3]

Answer:

The Hydrostatic force is   F  =  137.2 kN

The location of pressure center is  Z  = 1.333 \ m  

Explanation:

From the question we are told that

   The height of the gate is  h =  3 \ m

     The weight of the gate is  w =  7 \  m

      The height of the water is  h_w  =  2 \ m

       The density of water is \rho_w  =  1000 \ kg/m^3

Note used h_w for height of water and height of gate immersed by water since both have the same value

The area of the gate immersed in water  is mathematically represented as

         A =  h_w  * w

substituting values

         A =  2*  7

         A =  14  \ m^2

The hydrostatic force is mathematically represented as

          F  =  \rho_w * g * h_f * A

Where

            h_f =h-  h_w

           h_f =3 -2

           h_f = 1\ m  

So  

              F  =  1000 * 9.8 * 1 * 14

            F  =  137.2 kN

The center of pressure is mathematically represented as

        Z  =  h_f + \frac{I_g}{h_f * A}

Where I_g is the moment of inertia of the gate which mathematically represented as

            I_g =  \frac{w * h_w^2}{12}

The h_w is the height of gate immersed in water

            I_g =  \frac{7  * 2^2 }{12}

             I_g = 4.667\ kg  m^2

Thus  

        Z  = 1  + \frac{4.66}{1 * 14}

        Z  = 1.333 \ m

3 0
3 years ago
The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of
alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

The capacitance can be expressed in terms of the Area, the permeability constant and the diameter:

C = \frac{\epsilon_0 A}{d}

Where,

\epsilon_0 = Permeability constant

A = Cross-sectional Area

d = Diameter

Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to \rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

Q = CV

Q = \frac{\epsilon A}{d}(Ed)

Q = \epsilon_0 AE

Q = \epsilon_0 \pi(\frac{d}{2})^2E

Q = \frac{\epsilon \pi d^2E}{4}

Re-arranging the equation to find the diameter of the disks, the equation will be:

d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}

Replacing,

d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}

d = 0.0299m

Therefore the diameter of the disks is 0.03m

8 0
3 years ago
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