metres to kilometres = 1/1000
8 m ⇒ 0.008 km
metres to centimetres = × 100
8 m ⇒ 800 cm
Answer:
B. 7.07 m/s
Explanation:
The velocity of the stone when it leaves the circular path is its tangential velocity, , which is given by
where is the angular speed and is the radius of the circular path.
is given by
where is the frequency of revolution.
Thus
Using values from the question,
<em>Note the conversion of 75 cm to 0.75 m</em>
Answer:
149.05J
Explanation:
Hello,
Data;
Weight = 12N
x = 80miles
Radius of the moon = 1079.4mi
W = mg
But gravity at moon = ⅙ the gravity on earth
12 = ⅙ × m
M = 2kg
Mass of the module = 2kg
K = F.x
F(x) = k / x²
2 = k / (1079.4)²
k = 2.33×10⁶
Work = ∫f.dx
work = ∫₁₀₇₉.₄¹¹⁵⁹ . (2.33×10⁶/x²).dx
Work = (-2.33×10⁶) ×(¹/₁₁₅₉ - ¹/₁₀₇₉)
work = 149.05J
Here is the solution to your problem