The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
<span>First we can find the circumference of the whole circle with a radius of 5 feet.
circumference = 2 pi radius
circumference = (2 pi) (5 feet)
circumference = (10 pi) feet
From one high point to the other high point, the string moves through an angle of 10 degrees. Since a full circle is 360 degrees, this angle is 1/36 of a full circle.
Therefore, the arc length is 1/36 of the whole circumference.
arc length = (1/36) (circumference)
arc length = (1/36) (10 pi) feet
arc length = 0.873 feet</span>
Answer:
5.7 x 10^12 C
Explanation:
Let the charge on earth and moon is q.
mass of earth, Me = 5.972 x 10^24 kg
mass of moon, Mm = 7.35 x 10^22 kg
Let d be the distance between earth and moon.
the gravitational force between them is
![F_{g}=G\frac{M_{e} \times M_{m}}{d^{2}}](https://tex.z-dn.net/?f=F_%7Bg%7D%3DG%5Cfrac%7BM_%7Be%7D%20%5Ctimes%20M_%7Bm%7D%7D%7Bd%5E%7B2%7D%7D)
The electrostatic force between them is
![F_{e}=\frac{Kq^{2}}{d^{2}}](https://tex.z-dn.net/?f=F_%7Be%7D%3D%5Cfrac%7BKq%5E%7B2%7D%7D%7Bd%5E%7B2%7D%7D)
According to the question
1 % of Fg = Fe
![0.01 \times 6.67\times10^{-11}\frac{5.97 \times 10^{24}\times7.35 \times 10^{22}}{d^{2}}=9 \times 10^{9}\frac{q^{2}}{d^{2}}](https://tex.z-dn.net/?f=0.01%20%5Ctimes%206.67%5Ctimes10%5E%7B-11%7D%5Cfrac%7B5.97%20%5Ctimes%2010%5E%7B24%7D%5Ctimes7.35%20%5Ctimes%2010%5E%7B22%7D%7D%7Bd%5E%7B2%7D%7D%3D9%20%5Ctimes%2010%5E%7B9%7D%5Cfrac%7Bq%5E%7B2%7D%7D%7Bd%5E%7B2%7D%7D)
![2.927 \times 10^{35}=9 \times10^{9}q^{2}](https://tex.z-dn.net/?f=2.927%20%5Ctimes%2010%5E%7B35%7D%3D9%20%5Ctimes10%5E%7B9%7Dq%5E%7B2%7D)
![3.25 \times 10^{25}=q^{2}](https://tex.z-dn.net/?f=3.25%20%5Ctimes%2010%5E%7B25%7D%3Dq%5E%7B2%7D)
q = 5.7 x 10^12 C
Thus, the charge on earth and the moon is 5.7 x 10^12 C.
Angular frequency in radian per second for 20 vibrations in 10 seconds is 12.6 rad/s
<h3>What is Angular frequency?</h3>
Angular frequency is the number of vibrations in radian per second.
The total number of vibrations n is 20 and the time taken for these vibrations is 10 s
The frequency of the vibrations will be
f = 20 / 10 = 2 Hz
Angular frequency is related to the frequency as
ω = 2πf
ω=2π × 2
ω = 12.6 rad/s
Thus, the angular frequency is 12.6 rad/s.
Learn more about Angular frequency.
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Answer:
Explanation:
Let the forward displacement is taken is positive, and the backward displacement is taken is negative.
first displacement = + 18 cm
second displacement = - 6 cm
third displacement = - 12 cm
net displacement = 18 - 12 - 6 = 0 cm