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SpyIntel [72]
3 years ago
5

A construction crew is lengthening a road. Let L be the total length of the road (in miles). Let D be the number of days the cre

w has worked. Suppose that L=3D+200 gives L as a function of D. The crew can work for at most 90 days. Identify the correct description of the values in both the domain and range of the function. Then, for each, find the most appropriate set of values. PLEASE PLEASE PLEASE HELP!!! I WILL GIVE BRAINLIEST!!!
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

Answer:

Step-by-step explanation A  construction crew is lengthening a road. Let  L  be the total length of the road (in miles). Let  D  be the number of days the crew has worked. Suppose that  =L+4D200   gives  L  as a function of  D . The crew can work for at most  70  days.   =L+4D200 is not clear, not an equation.on:

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X = 8 and yeah that’s all

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500 grams of tomatoes cost £1.76 how much will 1.75kg cost??
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3 0
3 years ago
Hep asappppppppppppp
schepotkina [342]

Answer:

(6 , -1)

Step-by-step explanation:

2x+  y  = 11   ----------------(I)

y = 11 - 2x --------------------(II)

\frac{1}{2}x - 5y = 8

Multiply the whole equation by 2

2*\frac{1}{2}x -2*5y = 2*8

x - 10y = 16 --------------------(III)

Substitute y = 11- 2x in equation (III)

x - 10(11 - 2x) = 16

x - 110 + 20x = 16

21x - 110 = 16

21x = 16 +110

21x = 126

x = 126/21

x = 6

Plugin x = 6 in equation (II)

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5 0
2 years ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
In triangle XYZ, m∠Z &gt; m∠X + m∠Y. Which must be true about △XYZ?
Solnce55 [7]
Since z is GREATER THAN two angles in the triangle it must be obtuse..
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m∠X + m∠Y < 90°
4 0
3 years ago
Read 2 more answers
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