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aivan3 [116]
3 years ago
13

Plz help i need it!!!!!!!

Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

b

Step-by-step explanation:

please answer my last question on my profile for 23 points

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A life guard in a tower 20 ft above sea level spots a struggling surfer at an angle of depression of 15 . How far is the surfer
GalinKa [24]

Answer: 19.31\ ft

Step-by-step explanation:

Given

The tower is at a height of h=20\ ft

the angle of depression is 15^{\circ}

Suppose the surfer is x ft away from the base of the tower

\therefore \text{From the figure, we can write}\\\\\Rightarrow \cos 15^{\circ}=\dfrac{x}{h}\\\\\Rightarrow x=h\cos 15^{\circ}\\\Rightarrow x=20\cos 15^{\circ}\\\Rightarrow x=19.31\ ft

Therefore, the surfer is at a distance of 19.31 ft from the base of the tower.

7 0
3 years ago
I need help on #2 if 1 meter is 1000 kilometers what would the answer be
anastassius [24]
120 times because 300 divided by 25
4 0
3 years ago
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If the coefficient of determination for a data set is 0.75 and the SSE for the data set is 13, what is the SST for the data set?
nadya68 [22]
Answer : SSE = 9
r^2 = 0.75
r^2 = 1 - (SSE/SST)
SSE/SST = 1 - r^2 = 1 - 0.75 = 0.25
<span>SST = 9/0.25 = 36</span>
8 0
3 years ago
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A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
Which of the following equations will produce the graph shown below
Katen [24]

Answer:

B. 6x^{2}+6y^{2}=144

Step-by-step explanation:

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