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julia-pushkina [17]
3 years ago
13

Evaluate the dot product a⃗ ⋅b⃗ of a⃗ =3i^−8j^ and b⃗ =−2i^−6j^.

Mathematics
1 answer:
Mkey [24]3 years ago
4 0
The "dot product" of two vectors has several different formulas.

Since you are given the x- and y-coordinates of both vectors a and b, we can apply the formula

a dot b  = ax*bx + ay*by, where ax=x-component of vector a, by=y comp of vector b, and so on.  

So, for the problem at hand, ax * bx + ay * by becomes

3(-2) + (-8)(-6) = -6 + 48 = 42 (answer).  Note that the dot product (or "scalar product" is itself a scalar.
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3 years ago
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MUST SHOW WORK. <br> please do this ASAP!<br> This is about numerical expressions!
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\huge\text{Hey there!}

\mathsf{2(4 - 1)^2 - 3 + 2(5)}

\mathsf{4 - 1 = \bf 3}

\mathsf{= 2(3^2) - 3 + 2(5)}

\mathsf{3^2}\\\mathsf{= 3\times3}\\\mathsf{= \bf 9}

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\mathsf{= 15 + 2(5)}

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3 years ago
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<img src="https://tex.z-dn.net/?f=x%20%5Cdiv%202%20%2B%20x%20%5Cdiv%203%20%3D%201%20" id="TexFormula1" title="x \div 2 + x \div
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Answer:

Exact form : x=6/5

Decimal form : x=1.2

Mixed Number form : x=1 1/5

Step-by-step explanation: Solve for x by simplifying both sides of he equation, then isolating the variable.

Hope this helps you out! ☺

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2 years ago
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