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Alexeev081 [22]
3 years ago
11

An image of a right triangle is shown with an angle labeled x. If tan x° = 11 divided by r and cos x° = r divided by s, what is

the value of sin x°?
Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Answer:

sin(x)=\frac{11}{s}

Step-by-step explanation:

we know that

In a right triangle

the tangent of an angle is equal to divide the opposite side of the angle by the adjacent side of the angle

the function cosine of an angle is equal to divide the adjacent side of the angle by the hypotenuse

the function sine of an angle is equal to divide the opposite side of the angle by the hypotenuse

so

<u>In this problem we have</u>

tan(x)=\frac{11}{r}

the opposite side angle x is equal to 11\ units

the adjacent side angle x is equal to r\ units

cos(x)=\frac{r}{s}

the adjacent side angle x is equal to r\ units

the hypotenuse is equal to s\ units

Hence

sin(x)=\frac{11}{s}


Natali [406]3 years ago
6 0
Sin x = 11/s because it’s opposite/hypotenuse.
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<h3>Answer:  Independent</h3>

For two events A and B, if the occurrence of either event in no way affects the probability of the occurrence of the other event, then the two events are considered to be <u>  independent  </u> events.

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Step-by-step explanation:

  • x + y + z = -3  --> (1)
  • 3y - z = 4   --> (2)
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<u>Add up (1) and (2)</u>

  • x + 3y + y + z - z = -3 + 4 ⇒ x + 4y = 1  --> (4)

<u>Double (2) and subtract from (3)</u>

  • 2x - y - 2z - 2(3y - z) = -5 - 2(4) ⇒ 2x - y - 2z - 6y + 2z = -5 - 8
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<u>Double (4) and subtract (5)</u>

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<u>Finding x</u>

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<u>Finding z</u>

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<u>So the answer is: </u>

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