Ask question

Ask question

All categories

Alexeev081 [22]

3 years ago

11

An image of a right triangle is shown with an angle labeled x. If tan x° = 11 divided by r and cos x° = r divided by s, what is

the value of sin x°?

2 answers:

dlinn [17]3 years ago

8 0

Answer:

$sin(x)=\frac{11}{s}$

Step-by-step explanation:

we know that

In a right triangle

the tangent of an angle is equal to divide the opposite side of the angle by the adjacent side of the angle

the function cosine of an angle is equal to divide the adjacent side of the angle by the hypotenuse

the function sine of an angle is equal to divide the opposite side of the angle by the hypotenuse

so

<u>In this problem we have</u>

$tan(x)=\frac{11}{r}$

the opposite side angle x is equal to $11\ units$

the adjacent side angle x is equal to $r\ units$

$cos(x)=\frac{r}{s}$

the adjacent side angle x is equal to $r\ units$

the hypotenuse is equal to $s\ units$

Hence

$sin(x)=\frac{11}{s}$

Natali [406]3 years ago

6 0

Sin x = 11/s because it’s opposite/hypotenuse.

You might be interested in

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

kelly will roll a number cube labeled 1 to 6. what is the probability kelly will roll a number greater than 3?

guapka [62]

Answer:

%50

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Write this trinomial in factored form 2a^2 +7a+3

EleoNora [17]

Answer:

(2a + 1)(a + 3) = 2a² + 7a + 3

8 0

3 years ago

Juan got on an elevator at the middle floor of a building, went up 4 floors, down 3 floors, up one floor, down 9 floors, where h

xenn [34]

There are 14 floors in the building, because since Juan went up 4 floors, down 3 floors, and up one floor; so we know that he is 2 floors above from where he originally started. Once he went down 9 floors he passed the starting point and went to the bottom of the building. So, the middle must have been the 7th floor. Once I knew that I multiplied 7*2 and it got me 14. So in total there are 14 floors. I hope this helped ^^

5 0

3 years ago

What does 49.39 round to.

Verizon [17]

If you want to round 49.39 to the nearest tenths place you will have to look at your tenths digit. The digit is 3, right? Look at the next number after 3. It is the number 9 for the hundredths place. If the number is bigger than 5 you round it. If it is smaller, you keep it the same. 9 is bigger than 5 so you make the 3 into a 4. Then, you're answer is 49.4 or 49.40 (Which are basically the same answer) It also works the same with the other digits. Simple, right? :)

4 0

3 years ago