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Alexeev081 [22]
3 years ago
11

An image of a right triangle is shown with an angle labeled x. If tan x° = 11 divided by r and cos x° = r divided by s, what is

the value of sin x°?
Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Answer:

sin(x)=\frac{11}{s}

Step-by-step explanation:

we know that

In a right triangle

the tangent of an angle is equal to divide the opposite side of the angle by the adjacent side of the angle

the function cosine of an angle is equal to divide the adjacent side of the angle by the hypotenuse

the function sine of an angle is equal to divide the opposite side of the angle by the hypotenuse

so

<u>In this problem we have</u>

tan(x)=\frac{11}{r}

the opposite side angle x is equal to 11\ units

the adjacent side angle x is equal to r\ units

cos(x)=\frac{r}{s}

the adjacent side angle x is equal to r\ units

the hypotenuse is equal to s\ units

Hence

sin(x)=\frac{11}{s}


Natali [406]3 years ago
6 0
Sin x = 11/s because it’s opposite/hypotenuse.
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Correct answers only please!
MrRissso [65]

Answer:

23.6°

Step-by-step explanation:

In this question we have to use some trigonometry to work out angle XVW. Since we are working out angles all of the trigonometric functions will have to be to the ⁻¹. The first thing we need to identify is will formula will we use out of the following:

Sin⁻¹ = Opposite ÷ Hypotenuse

Tan⁻¹ = Opposite ÷ Adjacent

Cos⁻¹ = Adjacent ÷ Hypotenuse

-------------------------------------------------------------------------------------------------------

10 = Hypotenuse

4 = Opposite

-------------------------------------------------------------------------------------------------------

We know which formula to use because the length won't be in the triangle for example we will be using the Sin triangle because we don't have an adjacent. If we don't have an adjacent then the other formula's won't work.

Now we substitute in the values to find the value of angle XVW

Sin⁻¹ = Opposite ÷ Hypotenuse

Sin⁻¹ = 4 ÷ 10

The value of angle XVW is 23.57817848

6 0
3 years ago
Can someone pls help me with this question?
JulsSmile [24]

Answer:

c

Step-by-step explanation:

I think so I might not be right but I'm sure it's c

8 0
3 years ago
Write the factors for each number Then decide whether the number is prime or composite
Lina20 [59]

Answer:

Step-by-step explanation:

If it have more than 2 divider its composite but its divider is only one and its self only its prime.1 isn't neither prime nor composite

8 0
3 years ago
Find -7a-6B (Picture provided)
sertanlavr [38]

Answer:

Option c

-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

<em><u>Then we perform operation -7A </u></em>

-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)

<u><em>Now we perform operation -6B </em></u>

-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)

Now we add the resulting matrices

\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)

7 0
3 years ago
Part G
ycow [4]
Where is the problem?
5 0
2 years ago
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