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IgorC [24]
3 years ago
12

The diameter of Jupiter is 88,000 miles This is about 11.1 times the diameter of Earth What is the diameter of the earth

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0
Assuming that Jupiter and Earth are similar
linear sale factor=(diameter of Jupiter) /(diameter of earth)=11
thus:
diameter of earth=(diameter of Jupiter)/(linear scale factor)
=88000/11
=8000 miles
The diameter of earth is 8000 miles
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There are 220 students in Year 9
e-lub [12.9K]

Answer:

132 and 88

Step-by-step explanation:

If there are 20% more boys than girls, then this means that the total percentage of boys us 60% and girls is 40%.

0.6 * 220 = 132

0.4 * 220 = 88

There are 132 boys and 88 girls in year 9

5 0
2 years ago
Hisako sells dolls at her doll store. If she sells a doll for $35, and there is 6% sales tax, what is the tax amount a customer
Sloan [31]

Given:

The price of a doll = $35

Sales tax = 6%

To find:

The tax amount that a customer will pay on one doll.

Solution:

The price of doll is $35 and the sales tax is 6%, so the tax amount on a doll is 6% of 35.

\text{Tax amount}=35\times \dfrac{6}{100}

\text{Tax amount}=\dfrac{210}{100}

\text{Tax amount}=\dfrac{21}{10}

\text{Tax amount}=2.1

Therefore, the tax amount that a customer will pay on one doll is $2.1.

7 0
2 years ago
Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

3 0
3 years ago
jeanine Baker makes floral arrangements. She has 13 different cut flowers and plans to use 7 of them. How many different selecti
Ksju [112]

A total of 1,716 selections of the 7 flowers are possible.

Step-by-step explanation:

Step 1:

There are 13 flowers from which Jeanine Baker plans to use 7 of them.

To determine the number of selections that are possible we use combinations.

The formula for combinations is; ^{n} C_{r}=\frac{n !}{(n-r) ! r !}.

Step 2:

In the given formula, n is the total number of options and r is the number of options to be selected.

For this question, n = 13 and r=7.

So ^{13} C_{7}=\frac{13 !}{(13-7) ! 7 !} = \frac{13 !}{(6) ! 7 !} = 1,716.

So a total of 1,716 selections are possible.

3 0
3 years ago
-8b-32 what is the answer with work?
Crank
Well the LCM (lowest common multiples) for 8 and 32 would be 4. So plug 4 into "b" -8×4-32. -8×4=32. -32-32. Since you can't subtract 32 and 32 you add! Which gives you -64.

Hope this helps (:
7 0
3 years ago
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