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Kryger [21]
3 years ago
7

If one knows only the constant resultant force acting on an object and the time during which this force acts

Physics
1 answer:
Alenkinab [10]3 years ago
5 0

Explanation:

  • We know that Newton's second law of motion gives the measure of external force acting on an object. It says that the rate of change of linear momentum of an object is directly proportional to the external applied force. It is given by :

F=\dfrac{\Delta p}{\Delta t}

Since, p = mv m is mass and v is velocity.

F=\dfrac{m(v-u)}{ t}\\\\F\times t=m(v-u)

So, if one knows only the constant resultant force acting on an object and the time during which this force acts, one can determine the change in momentum of the impulse.

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8–4. The tank of the air compressor is subjected to an internal pressure of 90 psi. If the internal diameter of the tank is 22 i
slamgirl [31]

Answer:

The stress S = 1935 [Psi]

Explanation:

This kind of problem belongs to the mechanical of materials field in the branch of the mechanical engineering.

The initial data:

P = internal pressure [Psi] = 90 [Psi]

Di= internal diameter [in] = 22 [in]

t = wall thickness [in] = 0.25 [in]

S = stress = [Psi]

Therefore

ri = internal radius = (Di)/2 - t = (22/2) - 0.25 = 10.75 [in]

And using the expression to find the stress:

S=\frac{P*D_{i} }{2*t} \\replacing:\\S=\frac{90*10.75 }{2*0.25} \\S=1935[Psi]

In the attached image we can see the stress σ1 & σ2 = S acting over the point A.

4 0
3 years ago
Light incident on a surface at an angle of 45 degrees undergoes diffused reflection. At what angle will it reflect?
Alexus [3.1K]
 at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle
4 0
3 years ago
Read 2 more answers
How would I calculate the X from a known velocity when launching a ball off a table?
Anon25 [30]
Here are the steps you would need to follow:

#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.

With this information in front of you, you'll have a much better chance
of answering the question.

With none of it in front of me, I have no chance at all.
4 0
3 years ago
Read 2 more answers
Saturated water vapor at 200 kPa is condensed into a saturated liquid via a constant-pressure process inside of a piston-cylinde
evablogger [386]

Answer:

The process is not possible

Explanation:

if we want to determine if the process is possible , we can check with the second law of thermodynamics

ΔS≥ ∫dQ/T

for a constant temperature process ( condensation)

ΔS≥ 1/T ∫dQ

and from the first law of thermodynamics

ΔH = Q - ∫VdP , but P=constant → dP=0 → ∫VdP=0

Q=ΔH

then

ΔS≥ΔH/T

from steam tables

at P= constant = 200 Kpa → T= 120°C = 393 K

at P= constant → H vapor = 2201.5 kJ/kg ,  H liquid = 1.5302 kJ/kg

, S vapor= 7.1269 kJ/kg , S liquid 1.7022 kJ/kg

therefore

ΔH = H vapor - H liquid = 2201.5 kJ/kg -  1.5302 kJ/kg = 2199.9698 kJ/kg

ΔS = S vapor - S liquid = 7.1269 kJ/kg - 1.7022 kJ/kg = 5.4247 kJ/kg

therefore since

ΔS required  = ΔH/T = 2199.9698 kJ/kg/(393 K)= 5.597 kJ/kg K

and

ΔS= 5.4247 kJ/kg  ≤ ΔS required=5.597 kJ/kg K

the process is not possible

5 0
3 years ago
PLEASE HELP ME
son4ous [18]

Answer:

synthesis is correct answer.

6 0
3 years ago
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