All categories

3 years ago

How would I calculate the X from a known velocity when launching a ball off a table?

2 answers:

4 0

Here are the steps you would need to follow:

#1). Define what 'the 'X is, and how it's related to the ball.
#2). Be clear on how 'the X' is related to the 'known velocity'.
#3). Identify how the 'known velocity' is related to the action of the ball when it's launched.

With this information in front of you, you'll have a much better chance
of answering the question.

With none of it in front of me, I have no chance at all.

mario62 [17]3 years ago

3 0

Use the equation:

$X=ut+ \frac{1}{2} at^{2}$
where u is the initial velocity, a is the acceleration downwards (in this case $a=g=9.81m s^{-2}$ )

Hope this helps :)

You might be interested in

Red light of wavelength 651 nm produces photoelectrons from a certain photoemissive material. Green light of wavelength 521 nm p

Mnenie [13.5K]

Answer:

material work function is 0.956 eV

Explanation:

given data

red wavelength 651 nm

green wavelength 521 nm

photo electrons = 1.50 × maximum kinetic energy

to find out

material work function

solution

we know by Einstein photo electric equation that is

for red light

h ( c / λr ) = Ф + kinetic energy

for green light

h ( c / λg ) = Ф + 1.50 × kinetic energy

now from both equation put kinetic energy from red to green

h ( c / λg ) = Ф + 1.50 × (h ( c / λr ) - Ф)

Ф =( hc / 0.50) × ( 1.50/ λr - 1/ λg)

put all value

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50) × ( 1.50/ λr - 1/ λg)

Ф =( 6.63 × $10^{-34}$ (3 × $10^{8}$ ) / 0.50 ) × ( 1.50/ 651× $10^{-9}$ - 1/ 521 × $10^{-9}$ )

Ф = 1.5305 × $10^{-19}$ J × ( 1ev / 1.6 × $10^{-19}$ J )

Ф = 0.956 eV

material work function is 0.956 eV

4 0

3 years ago

Read 2 more answers

One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.

alexandr402 [8]

Answer:

The value is $\lambda = 2 \ m$

Explanation:

From the question we are told that

The distance of the speaker from the second speaker to the east is $d = 3 \ m$

The distance of the speaker from the listener to the south is $a = 4 \ m$

Generally given that if the speaker move in any direction, their sound become louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

$y = \frac{\lambda}{2}$

Generally considering the orientation of the speakers and applying Pythagoras theorem we see that distance from the second speaker to the listener is mathematically represented as

$b = \sqrt{d^ 2 + a^2 }$

=> $b = \sqrt{3^ 2 + 4^2 }$

=> $b = 5$

Generally the path difference between the two speaker with respect to the listener is

$y = b - a$

=> $y = 5 - 4$

=> $y = 1$

$1 = \frac{\lambda}{2}$

=> $\lambda = 2 \ m$

4 0

3 years ago

Using Ohms Law, calculate the current that would exist in a circuit having a voltage of 240V experiencing 110 Ohms of resistance

anygoal [31]

To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)

To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)

To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)

8 0

3 years ago

Carbon nanotubes are made of the same material as the graphite found in pencils, a material soft enough to leave an image on

Leni [432]

They are composed of unbroken chains of covalent carbon to carbon bonds

Explanation:

6 0

3 years ago

That which type of boundary do lithospheric plates collide

satela [25.4K]

Answer

The type of boundary formed when lithospheric plates collide is called Convergent boundary

Explanation

When plates of the lithosphere collide, they form a sub-duction zone where the denser plate will be subdued underneath the less dense one. The one subdued later melts and get destroyed. This boundary occurs when; ocean crust meets ocean crust, when oceanic and continental crust meet and where continental crust meets continental crust.

3 0

3 years ago