Ruff's image is 50m behind the mirror surface and the image is also 3m tall.
This is because it is a plane mirror.
Answer:
The distance covered by the sprinter, s = 40 m
Explanation:
Given data,
The initial velocity of the sprinter, u = 0 m/s
The acceleration of the sprinter, a = 5 m/s²
The time period of acceleration of the sprinter, t = 4 s
Using the II equations of motion
s = ut + ½ at²
= 0 + ½ (5) (4)²
= 40 m
Hence, the distance covered by the sprinter, s = 40 m
Answer:
The correct answer is option a.
Explanation:
Conservation of momentum :

Where :
= masses of object collided
= initial velocity before collision
= final velocity after collision
We have :
Two equal-mass carts roll towards each other.

Initial velocity of 
Initial velocity of
(opposite direction)
Final velocity of
(same direction )
Final velocity of
(same direction)


v = 0.5 m/s
rg135
The speed of the carts after their collision is 0.5 m/s.
The solution for this problem is:
500 revolution per
minute = 8.33rev /s = 2π*8.33 rad /s = 52.36 rad /s
Angular velocity ω = 2π N
Angular acceleration α= (ω2 - ω1) /t
ω2 = 0
α = - ω1/t = -2π N /t
N = 500 rpm = 8.33 r p s.
α = -2π 8.33 /2.6 =- 20 rad/s^2