The energy transferred by a force to a moving object?
2 answers:
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1) The electric force changes by a factor of 25
2) The electric force changes by a factor of 16/9
Explanation:
1)
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, let's call F the initial force between the two charges when they are at a distance of r.
Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is
r' = 5r
Therefore, the new force between the charges is:
So, the force has changed by a factor of 25.
2)
The original force between the two charges is
In this problem, we have:
- The distance between the charges is changed by a factor of 6:
r' = 6r
- The charges are both changed by a factor of 8:
Substituting into the equation, we find the new force:
So, the force has changed by a factor of 16/9.
Learn more about electric force:
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Answer: The question is incomplete or some details are missing. Here is the complete question ; (a) The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows uniformly with acceleration of −5.55 m/s2 for 4.05 s, making straight skid marks 63.0 m long, all the way to the tree. With what speed (in m/s) does the car then strike the tree? m/s
(b) What If? If the car has the same initial velocity, and if the driver slams on the brakes at the same distance from the tree, then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2
a ) With what speed (in m/s) does the car then strike the tree? m/s = 4.3125m/s
b) then what would the acceleration need to be (in m/s2) so that the car narrowly avoids a collision? m/s2 = -5.696m/s2
Explanation:
The detailed steps and calculation is as shown in the attached file.
