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Elanso [62]
4 years ago
6

If mechanical energy is conserved, then a pendulum that has a potential energy of 20 J at its highest point and 0.5 J at its low

est point has _____ as its kinetic energy at its lowest point.
20 J
0.5 J
19.5 J
20.5 J
Physics
1 answer:
liraira [26]4 years ago
4 0
At the highest point: kinetic energy is 0 due to the speed  is 0

So the total mechanical energy is 20

Assume no frictions present, then the mechanical energy is conserved

So at the lowest point, kinetic energy = mechanical energy - potential energy

Answer will be 20 - 0.5 = 19.5 J
You might be interested in
A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction?
g100num [7]
It would be helpful if you draw the figure of the problem. You will see that a right triangle would be constructed by the problem where 19.0 is the angle between the hypotenuse and the base of the triangle. It is said that the force acting is said to be 9.0 N  at the said angle to the horizontal. Using trigonometric relations,

cos 19 = adjacent / hypotenuse = horizontal component / 9
horizontal component = 8.51 N
5 0
3 years ago
Read 2 more answers
4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not
vampirchik [111]

The ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

f = \frac{c}{\lambda}

where

f is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz

For the UVB, the range of wavelength is 280 nm - 320 nm, so

\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz

So the ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0
3 years ago
Is electricity a compound, element, or a mixture?
sveta [45]
Electricity is a compound
3 0
4 years ago
A 5.0-kg mass is placed at (3.0, 4.0) m, and a 6.0-kg mass is placed at (3.0, -4.0) m. What is the moment of inertia of this sys
Harrizon [31]

Answer:

the moment of inertia of this system of masses about the y-axis is 99 kgm²

Explanation:

Given the data in the question;

mass m₁ = 5.0 kg at point ( 3.0, 4.0 )

mass m₂ = 6.0 kg at point ( 3.0, -4.0 )

Now, Moment of inertia I of this system of masses about the y-axis will be;

Moment of inertia Iₓ = mixi²

Moment of inertia I = m₁x₁² + m₂x₂²

we substitute

Moment of inertia I = [ 5.0 × ( 3 )² ]  + [ 6.0 × ( 3 )² ]

Moment of inertia I = [ 5.0 × 9 ]  + [ 6.0 × 9 ]

Moment of inertia I = 45 + 54

Moment of inertia I = 99 kgm²

Therefore, the moment of inertia of this system of masses about the y-axis is 99 kgm²

7 0
3 years ago
HEEEEEEEEEEELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! ASAP!!!!!!
Artemon [7]
Relax.  Everything's under control.
If you use up all your exclamation points now, then
you won't have any left when you really need one.

          (1.4 x 10⁵ newton/coulomb) x (-1.6 x 10⁻¹⁹ coulomb)

     =    (1.4 x 10⁵  x  -1.6 x 10⁻¹⁹)  newton-coulomb/coulomb

     =    - (1.4 x 1.6) x 10⁵⁻¹⁹  newton

     =          - 2.24 x 10⁻¹⁴  newton
4 0
3 years ago
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