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Elanso [62]
4 years ago
6

If mechanical energy is conserved, then a pendulum that has a potential energy of 20 J at its highest point and 0.5 J at its low

est point has _____ as its kinetic energy at its lowest point.
20 J
0.5 J
19.5 J
20.5 J
Physics
1 answer:
liraira [26]4 years ago
4 0
At the highest point: kinetic energy is 0 due to the speed  is 0

So the total mechanical energy is 20

Assume no frictions present, then the mechanical energy is conserved

So at the lowest point, kinetic energy = mechanical energy - potential energy

Answer will be 20 - 0.5 = 19.5 J
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Answer:

a) The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

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Explanation:

a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)

T-(m*g)=m*a

Where:

T= thrust =3 *10^{4} N

m= module's mass =1 *10^{4} N

g= moon's gravity acceleration =1.623 \frac{m}{s^2}

a= module's acceleration during takeoff

Then, we can find the acceleration like this:

a=\frac{T}{m} -g=\frac{3*{10}^4 N}{1*{10}^4 kg}-1.623\frac{m}{s^2}

a=1.377 \frac{m}{s^2}

The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.

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Then we can say that a thrust of 3*10^{4} N won't be able to lift off the module from the Earth because it's smaller than the module's weight (9.8 *10^{4} N).

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