Density (d) which is the quotient when mass (m) is divided by volume (v) is usually reported in terms of g/mL.
d = m /v
Substituting the known values,
d = (1.62 kg) x (1000 g/ 1 kg) / (205 mL)
The answer would be approximately equal to 7.9 g/mL.
If in the solution, half of the added solute fails to dissolve. The solution started out supersaturated. The correct option is b.
<h3>What is supersaturation?</h3>
Supersaturation is the condition where the solutes exceed the amount that can be dissolved in a solution.
Supersaturation occurs when the solute no longer mix in the solution.
Thus, the correct option is b. The solution started out supersaturated.
Learn more about supersaturation
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We know that acids have a pH of under 7.
We also need to:
Set up an ICE table for the chemical reaction. Solve for the concentration of H3O+ using the equation for pH Use the concentration of H3O+ to solve for the concentrations of the other products and reactants.
Explanation:
Scandium has atomic number of 21. This means that in it's neutral state its going to have 21 electrons.
a) The full electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 3d1 4s2
The final electron is placed in the d orbital. The shell is 3d
(b) When scandium has a charge if +1, it has lost an electron. The total number of electrons would now be 21-1 = 20
The electronic configuration would be given as;
1s2 2s2 2p6 3s2 3p6 4s2
The electron in the 3d orbital would be removed.
