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Korvikt [17]
3 years ago
7

HELPP ME !!!! DUE NOW!!!!!!

Chemistry
2 answers:
Deffense [45]3 years ago
8 0

Answer:

the answer is

a

b

d

c

Explanation:

hopeit help

sukhopar [10]3 years ago
5 0

Answer:

A.seven

B.eight

D.five

Csix

Explanation:

Hope this help

Mark brainliest

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Calculate the mass of precipitate that forms when 250.0 mL of an aqueous solution containing 35.5 g of lead(II) nitrate reacts w
natulia [17]
<h3><u>Answer;</u></h3>

= 49.42 g

<h3><u>Explanation;</u></h3>

The equation for the reaction between Lead (ii) nitrate and sodium iodide;

Pb(NO3)2(aq) + 2 NaI(aq) ---> 2NaNO3(aq) + PbI2(s)

The precipitate formed in this equation is Lead iodide

We first calculate the moles of lead nitrate;

Moles = mass/molar mass

           = 35.5 g/ 331.2 g/mol

           = 0.1072 moles

The mole ratio of Pb(NO3)2 : PbI2 is 1 : 1

Therefore; the number of moles of lead iodide is 0.1072 moles

Mass = moles × molar mass

         = 0.1072 moles × 461.01 g/mol

         <u>= 49.42 g</u>

6 0
3 years ago
How many grams of O2(g) are needed to completely burn 15.6 g of C3H8(g)?
alexdok [17]
15.6gC3H8*44.1gC3H8*32gO2=11.32
7 0
4 years ago
Determine the number of grams of carbon 3.14x 1023 atoms of carbon
tiny-mole [99]
<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 6.26227 \ g \ C

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0
3 years ago
Read 2 more answers
What is the name of the uppermost layer of the atmosphere? Why does it feel cold there, even though the temperature can be very
Aleonysh [2.5K]
That would be the exosphere. The reason it feels cold, despite high temperatures, is due to lower air density.
Hope it helps!
5 0
4 years ago
Can we use water as a solvent to obtain ethyl butyrate?
klio [65]

Answer:

yes but it depends

Explanation:

7 0
3 years ago
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