<h3><u>Answer;</u></h3>
= 49.42 g
<h3><u>Explanation;</u></h3>
The equation for the reaction between Lead (ii) nitrate and sodium iodide;
Pb(NO3)2(aq) + 2 NaI(aq) ---> 2NaNO3(aq) + PbI2(s)
The precipitate formed in this equation is Lead iodide
We first calculate the moles of lead nitrate;
Moles = mass/molar mass
= 35.5 g/ 331.2 g/mol
= 0.1072 moles
The mole ratio of Pb(NO3)2 : PbI2 is 1 : 1
Therefore; the number of moles of lead iodide is 0.1072 moles
Mass = moles × molar mass
= 0.1072 moles × 461.01 g/mol
<u>= 49.42 g</u>
15.6gC3H8*44.1gC3H8*32gO2=11.32
<h3>
Answer:</h3>
6.26 g C
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 3.14 × 10²³ atoms C
[Solve] grams C
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
6.26227 g C ≈ 6.26 g C
That would be the exosphere. The reason it feels cold, despite high temperatures, is due to lower air density.
Hope it helps!