When copper (ii) oxide is heated in presence of hydrogen gas it produces copper metal and water vapor.
that is
CuO + H2 = Cu + H2O
The moles of copper metal produced is calculated as below
find the moles of CUO used
moles = mass/molar mass
=5.6/79.5 =0.07 moles
by use of mole ratio between CUO:Cu which is 1:1 the moles of Cu is also
=0.007 moles of Cu
Answer:
M = 184.1 g/mol
Explanation:
Given data:
Density = 5.95 g/L
Temperature = 100°C (100+273 = 373 K)
Pressure = 755 mmHg = (755/760 = 0.99 atm )
Molar mass of gas = ?
Formula:
d = PM/RT
Solution:
M = dRT / P
M = 5.95 g/L × 0.0821 atm.L/mol.K × 373 K/ 0.99 atm
M = 182.21atm.g/mol / 0.99 atm
M = 184.1 g/mol
C. 4 decorated cupcakes.
Because 12 divided by 3 = 4, so you can have 4 cupcakes each with 3 cherries
Fe^2 O^3 + 6HCl --> 2FeCl^3 + 3H^2 O