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elena55 [62]
3 years ago
7

What is the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 L of water? Enter the simplest whole number ratio in order of h

ydrogen to oxygen, respectively.
Chemistry
1 answer:
Nataly_w [17]3 years ago
4 0

Answer : The ratio of hydrogen and oxygen in water is, (2:1)

Explanation :

As we know that the chemical formula of water is, H_2O.

In H_2O, there are 2 atoms of hydrogen and 1 atom of oxygen.

As we are given that the volume of water is, 2 L. So, there is no matter what is the volume of water that means there is no role of volume of water.

The ratio of hydrogen and oxygen in water is, (2:1)

Thus, in 2 L volume of water, the ratio of hydrogen and oxygen in water is also same that is, (2:1)

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A sample of 1.00 moles of oxygen at 50°C and 98.6 kPa, occupies what volume?
enyata [817]

Answer:

27.22 dm³

Explanation:

Given parameters:

number of moles = 1 mole

temperature= 50°C, in K gives 50+ 273 = 323K

Pressure= 98.6kpa in ATM, gives 0.973 ATM

Solution:

Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.

The ideal gas law is mathematically expressed as,

Pv=nRT

where P is the pressure of the gas

V is the volume

n is the number of moles

R is the gas constant

T is the temperature

Input the parameters and solve for V,

0.973 x V = 1 x 0.082 x 323

V= 27.22 dm³

5 0
3 years ago
Mass of NaOH = 0.2 <br> Volume of solution 500 ml
Yuliya22 [10]
Density will be mass/volume= 0.2/500 = 0.0004
6 0
2 years ago
What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?
const2013 [10]

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

5 0
3 years ago
Read 2 more answers
What is the net force acting on a teddy bear being pulled to the right 67N and to ghe left 112N
noname [10]
|F|  = 112 - 67 = 45 N 

F = 45 N ( to the left)
3 0
3 years ago
Read 2 more answers
Given the following unbalanced equation:
antiseptic1488 [7]
<h3>Answer:</h3>

11.84 mol CoF₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[RxN - Balanced] CoCl₂ + F₂ → CoF₂ + Cl₂

[Given] 11.84 moles CoCl₂

[Solve] moles CoF₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CoCl₂ → 1 mol CoF₂

<u>Step 3: Stoich</u>

  1. [DA] Set up:                                                                                                       \displaystyle 11.84 \ mol \ CoCl_2(\frac{1 \ mol \ CoF_2}{1 \ mol \ CoCl_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 11.84 \ mol \ CoF_2
7 0
3 years ago
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