If -5/2 is a root of that 3rd degree polynomial, then when we do synthetic division on it we will get a remainder of 0, and the resulting numbers from our math will then become the coefficients to a new polynomial, one degree less than what we started with, called the depressed polynomial. Put -5/2 outside the "box" and the coefficients inside: -5/2 (2 7 1 -10). Bring down the
2 and multiply it by -5/2 to get -5. Put that -5 up under the 7 and add to get
2. Multiply that 2 by the -5/2 to get -5. Put that -5 up under the 1 and add to get
-4. Multiply that by -5/2 and get 10. Put that 10 up under the -10 and add to get a remainder of 0. Those bolded numbers now are the coefficients of our new polynomial, one degree less than what we started with. That polynomial is
. Now we need to factor that to find the other 2 roots to our polynomial. If we factor a 2 out we have
,That factors easily to 2(x+2)(x-1). That gives us x+2=0 and x = -2, x-1=0 and x = 1. The 3 solutions or zeros or roots are -5/2, -2, 1. There you go!
Answer:
1. True
2. False
3. False
Step-by-step explanation:
Answer:
its the first one! y = 3/2x - 11
Step-by-step explanation:
Answer:
That would be wrote as 12 1/3
For parallel lines, slopes are equal.
5x - 3y = -10
3y = 5x + 10
y = 5/3 x + 10/3
Required slope = 5/3