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3 years ago

15

WILL GIVE BRAINLIEST!!

2 answers:

zepelin [54]3 years ago

5 0

<u>C. c || d, Converse of the Corresponding Angles Theorem</u> <em>was the correct answer for me. </em>

mixas84 [53]3 years ago

3 0

Line a intersects both lines c and d.
Line a is a transversal to lines c and d.
Angles 10 and 14 are corresponding angles.
Since corresponding angles are congruent, lines a and c are parallel.
Line b has nothing to do with this question.
Answer is choice A.

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Point B is the midpoint of Line segment A C .

lara31 [8.8K]

Answer:

Angle ABC is bisected by BD

BC =Half AC

2 mangle DBC =mangle ABC

6 0

2 years ago

Suppose j varies jointly with g and v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.

vladimir2022 [97]

Answer:

$j=12$

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form $j = kgv$

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

$2 = k(4)(3)$

$2 = 12k$

$k=\frac{1}{6}$

The equation is equal to

$j=\frac{1}{6}gv$

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

$j=\frac{1}{6}(8)(9)$

$j=12$

3 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP MMMMMMMMMMMMMMMMEEEEEEEEEEEEEEEE

Fudgin [204]

Y=2x+1 I think this is correct but I don’t know how to do equations very well

3 0

2 years ago

For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

kvv77 [185]

Answer: Option C

$f(x) = x^2;\ k (x) = x ^ 2 -7$

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

$k (x) = f (x) + b$

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

$f (x) = x ^ 2$

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

$k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7$ .

Then the function k(x) that will have its vertex 7 units below f(x) is

$k (x) = x ^ 2 -7$

3 0

3 years ago

Harry's spell casting class lasts 5/6 of an hour each day. Today, he has been in the class for 2/5 of an hour so far. How much m

Anna007 [38]

30 minutes are left in the class.

5 0

3 years ago