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8090 [49]
3 years ago
3

Refer to the following gaseous molecules: (A) BeCl2 (B) SO2 (C) N2 (D) O2 (E) F2 Is best represented by two or more resonance fo

rms

Chemistry
1 answer:
Nikolay [14]3 years ago
0 0

Answer: SO2

Explanation:

The image below shows the resonance forms of SO2. Resonance forms are structures that are similar in energy and altogether describe the actual structure of a molecule. The real structure of the molecule is neither of the resonance forms but a hybrid of all the structures. Invocation of the idea of resonance simplifies apparent complexities such as equal bond length and bond angles.

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Sugar + water = 2) a solution
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3 years ago
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Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76
aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

4 0
3 years ago
Oxygen freezes at -219°c and boils at -183°c in which state is oxygen at -200°c​
vova2212 [387]

oxygen is in gaseous state at this temperature

4 0
3 years ago
A mains radio turns ________ energy into ______ energy and ______ energy.
liberstina [14]

Shooting a rubber band turns _________ energy into _______ energy Elastic potential energy into mechanical energy

The ___________ energy from the sun transforms into ____________ energy in plants

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A runner turns _______ energy into ________ energy

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A hand crank radio turns _____ energy into ______ energy into _____________ energy

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3 0
2 years ago
For the reaction: 2 A (g) + B (s)= 2 C(s) + D (g)
jolli1 [7]

Answer:

The value of the equilibrium constant = 5.213

Explanation:

Here K_p (equilibrium constant) is referred to as the  partial pressure of product divided by the  partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation .

As such only gas appear in K_p  expression as solids takes a value of 1;

SO ; in the  given equation from the question:

2 A (g) + B (s) ----> 2 C(s) + D (g)

K_p = \dfrac{[D]}{[A]^2}

K_p = \dfrac{2.71}{0.721^2}

K_p = 5.213

The value of the equilibrium constant = 5.213

8 0
3 years ago
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