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Tpy6a [65]
3 years ago
12

9. What lab equipment is used to spread heat when heating to prevent glassware from cracking

Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
It's called ”wire gauze”, a metal mesh used with a ring clamp to support glassware over a Bunsen burner. Spreads flame out for more even heating rates.

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Enter an equation showing how this buffer neutralizes added aqueous acid (HI). Express your answer as a chemical equation. Ident
andrey2020 [161]

Answer:

H^++NH_3\rightleftharpoons NH_4^+

Explanation:

Hello there!

In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:

H^++NH_3\rightleftharpoons NH_4^+

Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.

Best regards!

5 0
3 years ago
Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
5 0
3 years ago
Read 2 more answers
A scientist finds one carbon atom for every two oxygen atoms in a sample of compound x. for which other samples of compound x sh
Doss [256]

The formula or chemical formula of a compound is same irrespective of source / mode of synthesis . Thus if a sample of compound has one carbon atom for every two atoms of oxygen (CO2), the formula will remains the same

So the answer is that for all other samples the compound X should hold this ration true.

7 0
3 years ago
Read 2 more answers
Express the following numbers as decimals: (a) 1.52 x 10^-2, (b) 7.78 x 10^-8, (c) 1 x 10^-6, (d) 1.6001 x 10^3.
Alchen [17]

Answer :

(a) 0.0152

(b) 0.0000000778

(c) 0.000001

(d) 1600.1

Explanation :

Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example :

5000 is written as 5.0\times 10^3

889.9 is written as 8.899\times 10^{-2}

In this examples, 5000 and 889.9 are written in the standard notation and 5.0\times 10^3  and 8.899\times 10^{-2}  are written in the scientific notation.

(a) 1.52\times 10^{-2}

The standard notation is, 0.0152

(b) 7.78\times 10^{-8}

The standard notation is, 0.0000000778

(c) 1\times 10^{-6}

The standard notation is, 0.000001

(d) 1.6001\times 10^{3}

The standard notation is, 1600.1

5 0
3 years ago
Identify the item that does not have kinetic energy.
d1i1m1o1n [39]

Answer:

D

Explanation:

there is no other answer choice that does not move. This is a fool-proof question because all the other answer choices contain movement except the butterfly resting

4 0
3 years ago
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