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Elan Coil [88]
3 years ago
11

A gas storage tank has a volume of 3.5 X 105 L when the temperature is 27oC, and the pressure is 101 kPa. What is the new volume

of the tank if the temperature drops to -10oC and the pressure drops to 95 kPa ?
Chemistry
1 answer:
masha68 [24]3 years ago
8 0

Answer: 3.26x10^5L

Explanation:

P1 = 101kPa

P2 = 95kPa

T1 = 27°C = 27 +273 =300k

T2 = —10°C = —10 +273 = 263k

V1 = 3.5 x 10^5 L

V2 =?

P1V1 / T1 = P2V2 /T2

(101 x 3.5 x 10^5)/300 = (95xV2)/263

300x95xV2 = 101x 3.5x10^5x263

V2 = (101x 3.5x10^5x263) /(300x95)

V2 = 3.26x10^5L

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Answer:

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Explanation:

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kvasek [131]

Explanation:

A.

Yes

B.

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KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

C.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

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Number of moles = mass/molar mass

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= 0.1 mol.

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D.

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

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1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

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3 years ago
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The relationship between pressure and solubility of the gas is given by Henry's law as:

S_g = kP_g

where,

S_g is the solubility of the gas.

k is proportionality constant i.e. Henry's constant.

P_g is pressure of the gas.

k = 5.6 bar/mol/kg (given)

P_g = 0.13 bar (given)

Substituting the values,

S_g = 5.6 bar/mol/kg\times 0.13 bar = 0.728 mole/kg

To convert mole/kg to g/kg:

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0.728\times 78 = 56.784 g/kg

Now for converting into ppm:

Since, 1 ppm = 0.001 g/kg

So, 56.784\times 1000 = 56784 ppm.

Hence, the solubility of benzene in water at 25^{o} C in ppm is 56784 ppm.


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