Rising air in the tropics is called the Intertropical convergence zone and is a region of rising hot air. As it rises, the moisture in the air eventually reaches its saturation point and the moisture falls out as rain. This is why the tropics are know for their very heavy rainfall periods
Answer: Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is:
H2SO4(aq) + NaOH(aq) → Na2SO4(aq) + H2O(l)
A student who was asked to balance the reaction wrote the following:
H2SO4(aq) + Na2OH(aq) →Na2SO4(aq) + H3O(l)
Is this correct? Explain why or why not using what you know about the law of conservation of mass and chemical changes. If necessary, provide the correct balanced equation.
Explanation: The mass of the reactants must equal that of the products. This is because the masses of the products arise from the reactants and no mass is either created or destroyed. The total mass of the reactant must equal that of the product side and vice versa.
The student made an error of protonating the water molecule to H3O+ without a corresponding balance on the reactant side. In this case, it is wrong and ceases to be an equation. The product side masses don't equal the reactant side.
Balancing a chemical equation is done by first writing the correct chemical symbol. The moles and masses of each compound are cross-checked that they are equal on both sides of the equation.
The balanced equation is Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag
Step 1. Write the <em>unbalanced equation
</em>
Mg + AgNO₃ ⟶ Mg(NO₃)₂ + Ag
Step 2. Start with the<em> most complicated-looking formula</em> [Mg(NO₃)₂] and balance its atoms.
Mg: Already balanced —1 atom each side.
N: We need 2 N on the left. Put a 2 in front of AgNO₃.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + Ag
O: Already balanced —6 atom6 each side.
Step 3: Balance <em>Ag</em>
We have 2Ag on the left. We need 2Ag on the right.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + 2Ag
The answer is B. Enzymes.
Enzymes are biological catalysts that help cause reactions in your body.
Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
