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Svetlanka [38]
3 years ago
7

Which statement is true regarding the sublimation of dry ice (solid co2?

Chemistry
1 answer:
WINSTONCH [101]3 years ago
5 0
Sublimation is the process of phase conversion of a compound or any entity from a solid state to gas state. The process is the opposite of deposition which converts a gas into its solid counterpart. Sublimation entails greater entropy as gas components are more entropic than solids are.
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Why has the canals in Venice Italy cleared up during this time?
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Which of the following could be considered a scientific statement
aliina [53]
I think a scientific STATEMENT could be answer C
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3 years ago
Read 2 more answers
Need help with this please thanks
kolbaska11 [484]

Answer: 1. 2H_2+O_2\rightarrow 2H_2O

2. P_4+3O_2\rightarrow 2P_2O_3

3. N_2+3H_2\rightarrow 2NH_3

4. 2K+Cl_2\rightarrow 2KCl

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The given equations are balanced as:

1. 2H_2+O_2\rightarrow 2H_2O

2. P_4+3O_2\rightarrow 2P_2O_3

3. N_2+3H_2\rightarrow 2NH_3

4. 2K+Cl_2\rightarrow 2KCl

5 0
2 years ago
In class, sam learned that some theorists link happiness to productivity. from this, he developed the thought that happy employe
kipiarov [429]

<span>In the given example, it led Sam’s theory to produce a hypothesis. It is because the educated guess that he has made has been linked to the theory where in the theory is about happiness and production that led him to think that having happy employees will make more products to be produced.</span>

7 0
3 years ago
How many joules are released when one atom of americium 241, the isotope used in ionization-type smoke detectors, undergoes apha
klemol [59]

When Americium (Am-241) undergoes alpha decay(He-4) it forms neptunium (Np-237) based on the following pathway:

²⁴¹Am₉₅ → ²³⁷Np₉₃ + ⁴He₂

The energy released in given as:

ΔE = Δmc²

where Δm = mass of products - mass of reactants

                 = [m(Np-237) + m(He-4)] - [m(Am-241)]

                 = 237.0482+4.0015-241.0568 = -0.0073 g/mol = -7.3 * 10⁻⁶ kg/mol

ΔE = -7.3*10⁻⁶ kg/mol * (3*10⁸ m/s)² = -5.84*10¹¹ J/mol



4 0
2 years ago
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