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miv72 [106K]
3 years ago
7

What is the mass number for aluminum?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
7 0
<h3>Hello There!</h3>

The mass number is 26.9815

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Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A
Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k[NO_3][CO]

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)

The intermediate reaction of the mechanism follows:

Step 1:  2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}

Step 2:  NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[NO_3][CO]

Hence, the rate law for the reaction is written above.

5 0
4 years ago
An atom of lead has a radius of and the average orbital speed of the electrons in it is about . Calculate the least possible unc
victus00 [196]

The question is incomplete. Here is the complete question.

An atom of lead has a radius of 154 pm and the average orbitalspeed of the electron in it is about 1.8x10^{8} m/s. Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of lead. Write your answer as a percentage of the average speed, and round it to significant 2 digits.

Answer: v% = 0.21 m/s

Explanation: To calculate the uncertainty, use <u>Heisenberg's Uncertainty Principle</u>, which states that:  ΔpΔx≥\frac{h}{4\pi }

where h is <u>Planck's constant</u> and it is equal to 6.626.10^{-34}m²kg/s.

Since p (momentum) is p = m.v:

mΔv.Δx ≥ \frac{h}{4\pi }

Δv = \frac{h}{4\pi.x.m }

Given that: r = x = 1.54.10^{-10}m and mass of an electron is m=9.1.10^{-31}kg

Δv = \frac{6.626.10^{-34} }{4.3.14.1.54.10^{-10}.9.1.10^{-31}}

Δv = 0.0376.10^{7}

As percentage of average speed:

Δv.\frac{1}{v}.100% = \frac{0.0376.10^{7} }{1.8.10^{8} }.10² = 0.021.10 = 0.21%

The least possible uncertainty in a speed of an electron is 0.21%.

5 0
4 years ago
Q401YzNjg1/details
Sholpan [36]

Answer:

siof4 su8f adfi5 9id7 mdsyfn8 dsjfd8ie3 4yb4uj 4bnu4b 4uj4k 38h1487y76 bis4can d2f9id  fvs98nd

Explanation:us8s f7  ds8a das8 jf7sd 87sd 45s67f8

8 0
3 years ago
2. What type of bonding would be expected between the following atoms?
maksim [4K]
A.) covalent
c.) covalent
b.) ionic
d.) covalent
7 0
3 years ago
How many grams of mg are in 534g of mgo<br> ​
Kitty [74]

Answer:

0.534mg..

....

...

..

...

.

....

7 0
3 years ago
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